Question

我需要从两个不同的活动中获取字符串值，比如activity1和activity2，每个活动应该有最多4个edittext字段。所以总共八个字段应该在activity3中有序显示。我已经尝试了没有在activity3中显示的代码。

查看代码，

活性1

String namef = fname.getText().toString();
Intent first = new Intent(AssessmentActivity.this, Second.class);
first.putExtra("list1", namef);
startActivity(first);

String namel = lname.getText().toString();
Intent second = new Intent(AssessmentActivity.this, Second.class);
second.putExtra("list2", namel);
startActivity(second);

String phone = mob.getText().toString();
Intent third = new Intent(AssessmentActivity.this, Second.class);
third.putExtra("list3", phone);
startActivity(third);   

String mailid = email.getText().toString();
Intent fourth = new Intent(AssessmentActivity.this, Second.class);
fourth.putExtra("list4", mailid);
startActivity(fourth);

活性2

String cont = addr.getText().toString();
Intent fifth = new Intent(Second.this, Third.class);
fifth.putExtra("list5", cont);
startActivity(fifth);

String db = dob.getText().toString();
Intent sixth = new Intent(Second.this, Third.class);
sixth.putExtra("list6", db);
startActivity(sixth);

String nation = citizen.getText().toString();
Intent Seventh = new Intent(Second.this, Third.class);
Seventh.putExtra("list7", nation);
startActivity(Seventh);

String subject = course.getText().toString();
Intent Eight = new Intent(Second.this, Third.class);
Eight.putExtra("list8", subject);
startActivity(Eight);

*的 Activity3 *

TextView first = (TextView)findViewById(R.id.textView2);
String fieldone = getIntent().getStringExtra("list1" );
first.setText(fieldone);

TextView second = (TextView)findViewById(R.id.textView3);
String fieldtwo = getIntent().getStringExtra("list2" );
second.setText(fieldtwo);

TextView third = (TextView)findViewById(R.id.textView4);
String fieldthree = getIntent().getStringExtra("list3" );
third.setText(fieldthree);

TextView fourth = (TextView)findViewById(R.id.textView5);
String fieldfour = getIntent().getStringExtra("list4" );
fourth.setText(fieldfour);

TextView fifth = (TextView)findViewById(R.id.textView6);
String fieldfive = getIntent().getStringExtra("list5" );
fifth.setText(fieldfive);

TextView sixth = (TextView)findViewById(R.id.textView7);
String fieldsix = getIntent().getStringExtra("list6" );
sixth.setText(fieldsix);

TextView seventh = (TextView)findViewById(R.id.textView8);
String fieldseven = getIntent().getStringExtra("list7" );
seventh.setText(fieldseven);

TextView eight = (TextView)findViewById(R.id.textView3);
String fieldeight = getIntent().getStringExtra("list8");
eight.setText(fieldeight);

Answer 1

我认为您希望将所有这些内容传递到新活动中，而不是每个活动都启动新活动。

Intent first = new Intent(AssessmentActivity.this, Second.class);

String namef = fname.getText().toString();
first.putExtra("list1", namef);

String namel = lname.getText().toString();
first.putExtra("list2", namel);

String phone = mob.getText().toString();
first.putExtra("list3", phone);

String mailid = email.getText().toString();
first.putExtra("list4", mailid);

startActivity(first);

然后，在你的第二个（第二个活动）onCreate中，你可以拉出每一个并存储它们。然后，当您发送到第三个时，您可以将每个重新添加到意图中。

Intent fifth = new Intent(Second.this, Third.class);

fifth.putExtra("list1", namef_stored);
fifth.putExtra("list2", namel_stored);
fifth.putExtra("list3", phone_stored);
fifth.putExtra("list4", mailid_stored);

String cont = addr.getText().toString();
fifth.putExtra("list5", cont);

String db = dob.getText().toString();
fifth.putExtra("list6", db);

String nation = citizen.getText().toString();
fifth.putExtra("list7", nation);

String subject = course.getText().toString();
fifth.putExtra("list8", subject);

startActivity(fifth);

如何在活动1,2中显示活动3中的字符串？

1 个答案: