是否有比较版本号的标准习惯用法？我不能只使用直接的字符串比较，因为我还不知道最大点数发布的数量。我需要比较版本并保持以下：
1.0 < 1.1
1.0.1 < 1.1
1.9 < 1.10
答案 0 :(得分：159)
这个旧帖子的另一个解决方案（对于那些可能有帮助的帖子）：
public class Version implements Comparable<Version> {
private String version;
public final String get() {
return this.version;
}
public Version(String version) {
if(version == null)
throw new IllegalArgumentException("Version can not be null");
if(!version.matches("[0-9]+(\\.[0-9]+)*"))
throw new IllegalArgumentException("Invalid version format");
this.version = version;
}
@Override public int compareTo(Version that) {
if(that == null)
return 1;
String[] thisParts = this.get().split("\\.");
String[] thatParts = that.get().split("\\.");
int length = Math.max(thisParts.length, thatParts.length);
for(int i = 0; i < length; i++) {
int thisPart = i < thisParts.length ?
Integer.parseInt(thisParts[i]) : 0;
int thatPart = i < thatParts.length ?
Integer.parseInt(thatParts[i]) : 0;
if(thisPart < thatPart)
return -1;
if(thisPart > thatPart)
return 1;
}
return 0;
}
@Override public boolean equals(Object that) {
if(this == that)
return true;
if(that == null)
return false;
if(this.getClass() != that.getClass())
return false;
return this.compareTo((Version) that) == 0;
}
}
Version a = new Version("1.1");
Version b = new Version("1.1.1");
a.compareTo(b) // return -1 (a<b)
a.equals(b) // return false
Version a = new Version("2.0");
Version b = new Version("1.9.9");
a.compareTo(b) // return 1 (a>b)
a.equals(b) // return false
Version a = new Version("1.0");
Version b = new Version("1");
a.compareTo(b) // return 0 (a=b)
a.equals(b) // return true
Version a = new Version("1");
Version b = null;
a.compareTo(b) // return 1 (a>b)
a.equals(b) // return false
List<Version> versions = new ArrayList<Version>();
versions.add(new Version("2"));
versions.add(new Version("1.0.5"));
versions.add(new Version("1.01.0"));
versions.add(new Version("1.00.1"));
Collections.min(versions).get() // return min version
Collections.max(versions).get() // return max version
// WARNING
Version a = new Version("2.06");
Version b = new Version("2.060");
a.equals(b) // return false
编辑：
@daiscog：感谢您的评论，这段代码是针对Android平台开发的，并且根据Google的推荐，“匹配”方法检查整个字符串，而不像使用监管模式的Java。 （Android documentation - JAVA documentation）
答案 1 :(得分：90)
使用Maven非常容易：
import org.apache.maven.artifact.versioning.DefaultArtifactVersion;
DefaultArtifactVersion minVersion = new DefaultArtifactVersion("1.0.1");
DefaultArtifactVersion maxVersion = new DefaultArtifactVersion("1.10");
DefaultArtifactVersion version = new DefaultArtifactVersion("1.11");
if (version.compareTo(minVersion) < 0 || version.compareTo(maxVersion) > 0) {
System.out.println("Sorry, your version is unsupported");
}
您可以从this page获取Maven工件的正确依赖关系字符串：
<dependency>
<groupId>org.apache.maven</groupId>
<artifactId>maven-artifact</artifactId>
<version>3.0.3</version>
</dependency>
答案 2 :(得分：52)
以点作为分隔符对字符串进行标记，然后从左侧开始并排比较整数平移。
答案 3 :(得分：49)
您需要规范化版本字符串，以便对它们进行比较。像
这样的东西import java.util.regex.Pattern;
public class Main {
public static void main(String... args) {
compare("1.0", "1.1");
compare("1.0.1", "1.1");
compare("1.9", "1.10");
compare("1.a", "1.9");
}
private static void compare(String v1, String v2) {
String s1 = normalisedVersion(v1);
String s2 = normalisedVersion(v2);
int cmp = s1.compareTo(s2);
String cmpStr = cmp < 0 ? "<" : cmp > 0 ? ">" : "==";
System.out.printf("'%s' %s '%s'%n", v1, cmpStr, v2);
}
public static String normalisedVersion(String version) {
return normalisedVersion(version, ".", 4);
}
public static String normalisedVersion(String version, String sep, int maxWidth) {
String[] split = Pattern.compile(sep, Pattern.LITERAL).split(version);
StringBuilder sb = new StringBuilder();
for (String s : split) {
sb.append(String.format("%" + maxWidth + 's', s));
}
return sb.toString();
}
}
打印
'1.0' < '1.1' '1.0.1' < '1.1' '1.9' < '1.10' '1.a' > '1.9'
答案 4 :(得分：43)
最好重用现有代码， 拿Maven's ComparableVersion class
的优点：
不要包含对maven-artifact的依赖，因为这会引发各种传递依赖
答案 5 :(得分：30)
// VersionComparator.java
import java.util.Comparator;
public class VersionComparator implements Comparator {
public boolean equals(Object o1, Object o2) {
return compare(o1, o2) == 0;
}
public int compare(Object o1, Object o2) {
String version1 = (String) o1;
String version2 = (String) o2;
VersionTokenizer tokenizer1 = new VersionTokenizer(version1);
VersionTokenizer tokenizer2 = new VersionTokenizer(version2);
int number1 = 0, number2 = 0;
String suffix1 = "", suffix2 = "";
while (tokenizer1.MoveNext()) {
if (!tokenizer2.MoveNext()) {
do {
number1 = tokenizer1.getNumber();
suffix1 = tokenizer1.getSuffix();
if (number1 != 0 || suffix1.length() != 0) {
// Version one is longer than number two, and non-zero
return 1;
}
}
while (tokenizer1.MoveNext());
// Version one is longer than version two, but zero
return 0;
}
number1 = tokenizer1.getNumber();
suffix1 = tokenizer1.getSuffix();
number2 = tokenizer2.getNumber();
suffix2 = tokenizer2.getSuffix();
if (number1 < number2) {
// Number one is less than number two
return -1;
}
if (number1 > number2) {
// Number one is greater than number two
return 1;
}
boolean empty1 = suffix1.length() == 0;
boolean empty2 = suffix2.length() == 0;
if (empty1 && empty2) continue; // No suffixes
if (empty1) return 1; // First suffix is empty (1.2 > 1.2b)
if (empty2) return -1; // Second suffix is empty (1.2a < 1.2)
// Lexical comparison of suffixes
int result = suffix1.compareTo(suffix2);
if (result != 0) return result;
}
if (tokenizer2.MoveNext()) {
do {
number2 = tokenizer2.getNumber();
suffix2 = tokenizer2.getSuffix();
if (number2 != 0 || suffix2.length() != 0) {
// Version one is longer than version two, and non-zero
return -1;
}
}
while (tokenizer2.MoveNext());
// Version two is longer than version one, but zero
return 0;
}
return 0;
}
}
// VersionTokenizer.java
public class VersionTokenizer {
private final String _versionString;
private final int _length;
private int _position;
private int _number;
private String _suffix;
private boolean _hasValue;
public int getNumber() {
return _number;
}
public String getSuffix() {
return _suffix;
}
public boolean hasValue() {
return _hasValue;
}
public VersionTokenizer(String versionString) {
if (versionString == null)
throw new IllegalArgumentException("versionString is null");
_versionString = versionString;
_length = versionString.length();
}
public boolean MoveNext() {
_number = 0;
_suffix = "";
_hasValue = false;
// No more characters
if (_position >= _length)
return false;
_hasValue = true;
while (_position < _length) {
char c = _versionString.charAt(_position);
if (c < '0' || c > '9') break;
_number = _number * 10 + (c - '0');
_position++;
}
int suffixStart = _position;
while (_position < _length) {
char c = _versionString.charAt(_position);
if (c == '.') break;
_position++;
}
_suffix = _versionString.substring(suffixStart, _position);
if (_position < _length) _position++;
return true;
}
}
示例：
public class Main
{
private static VersionComparator cmp;
public static void main (String[] args)
{
cmp = new VersionComparator();
Test(new String[]{"1.1.2", "1.2", "1.2.0", "1.2.1", "1.12"});
Test(new String[]{"1.3", "1.3a", "1.3b", "1.3-SNAPSHOT"});
}
private static void Test(String[] versions) {
for (int i = 0; i < versions.length; i++) {
for (int j = i; j < versions.length; j++) {
Test(versions[i], versions[j]);
}
}
}
private static void Test(String v1, String v2) {
int result = cmp.compare(v1, v2);
String op = "==";
if (result < 0) op = "<";
if (result > 0) op = ">";
System.out.printf("%s %s %s\n", v1, op, v2);
}
}
<强>输出：
1.1.2 == 1.1.2 ---> same length and value
1.1.2 < 1.2 ---> first number (1) less than second number (2) => -1
1.1.2 < 1.2.0 ---> first number (1) less than second number (2) => -1
1.1.2 < 1.2.1 ---> first number (1) less than second number (2) => -1
1.1.2 < 1.12 ---> first number (1) less than second number (12) => -1
1.2 == 1.2 ---> same length and value
1.2 == 1.2.0 ---> first shorter than second, but zero
1.2 < 1.2.1 ---> first shorter than second, and non-zero
1.2 < 1.12 ---> first number (2) less than second number (12) => -1
1.2.0 == 1.2.0 ---> same length and value
1.2.0 < 1.2.1 ---> first number (0) less than second number (1) => -1
1.2.0 < 1.12 ---> first number (2) less than second number (12) => -1
1.2.1 == 1.2.1 ---> same length and value
1.2.1 < 1.12 ---> first number (2) less than second number (12) => -1
1.12 == 1.12 ---> same length and value
1.3 == 1.3 ---> same length and value
1.3 > 1.3a ---> first suffix ('') is empty, but not second ('a') => 1
1.3 > 1.3b ---> first suffix ('') is empty, but not second ('b') => 1
1.3 > 1.3-SNAPSHOT ---> first suffix ('') is empty, but not second ('-SNAPSHOT') => 1
1.3a == 1.3a ---> same length and value
1.3a < 1.3b ---> first suffix ('a') compared to second suffix ('b') => -1
1.3a < 1.3-SNAPSHOT ---> first suffix ('a') compared to second suffix ('-SNAPSHOT') => -1
1.3b == 1.3b ---> same length and value
1.3b < 1.3-SNAPSHOT ---> first suffix ('b') compared to second suffix ('-SNAPSHOT') => -1
1.3-SNAPSHOT == 1.3-SNAPSHOT ---> same length and value
答案 6 :(得分：12)
想知道为什么每个人都认为版本只是由整数组成 - 在我的情况下它不是。
为什么重新发明轮子（假设版本遵循Semver标准）
首先通过Maven安装https://github.com/vdurmont/semver4j
然后使用此库
Semver sem = new Semver("1.2.3");
sem.isGreaterThan("1.2.2"); // true
答案 7 :(得分：9)
public static int compareVersions(String version1, String version2){
String[] levels1 = version1.split("\\.");
String[] levels2 = version2.split("\\.");
int length = Math.max(levels1.length, levels2.length);
for (int i = 0; i < length; i++){
Integer v1 = i < levels1.length ? Integer.parseInt(levels1[i]) : 0;
Integer v2 = i < levels2.length ? Integer.parseInt(levels2[i]) : 0;
int compare = v1.compareTo(v2);
if (compare != 0){
return compare;
}
}
return 0;
}
答案 8 :(得分：2)
public int compare(String v1, String v2) {
v1 = v1.replaceAll("\\s", "");
v2 = v2.replaceAll("\\s", "");
String[] a1 = v1.split("\\.");
String[] a2 = v2.split("\\.");
List<String> l1 = Arrays.asList(a1);
List<String> l2 = Arrays.asList(a2);
int i=0;
while(true){
Double d1 = null;
Double d2 = null;
try{
d1 = Double.parseDouble(l1.get(i));
}catch(IndexOutOfBoundsException e){
}
try{
d2 = Double.parseDouble(l2.get(i));
}catch(IndexOutOfBoundsException e){
}
if (d1 != null && d2 != null) {
if (d1.doubleValue() > d2.doubleValue()) {
return 1;
} else if (d1.doubleValue() < d2.doubleValue()) {
return -1;
}
} else if (d2 == null && d1 != null) {
if (d1.doubleValue() > 0) {
return 1;
}
} else if (d1 == null && d2 != null) {
if (d2.doubleValue() > 0) {
return -1;
}
} else {
break;
}
i++;
}
return 0;
}
答案 9 :(得分：2)
如果您的项目中已经有Jackson，则可以使用com.fasterxml.jackson.core.Version：
import com.fasterxml.jackson.core.Version;
import org.junit.Test;
import static org.junit.Assert.assertTrue;
public class VersionTest {
@Test
public void shouldCompareVersion() {
Version version1 = new Version(1, 11, 1, null, null, null);
Version version2 = new Version(1, 12, 1, null, null, null);
assertTrue(version1.compareTo(version2) < 0);
}
}
答案 10 :(得分：2)
/**
* written by: Stan Towianski - May 2018
* notes: I make assumption each of 3 version sections a.b.c is not longer then 4 digits: aaaa.bbbb.cccc-MODWORD1(-)modnum2
* 5.10.13-release-1 becomes 0000500100013.501 6.0-snapshot becomes 0000600000000.100
* MODWORD1 = -xyz/NotMatching, -SNAPSHOT, -ALPHA, -BETA, -RC, -RELEASE/nothing return: .0, .1, .2, .3, .4, .5
* modnum2 = up to 2 digit/chars second version
* */
public class VersionCk {
private static boolean isVersionHigher( String baseVersion, String testVersion )
{
System.out.println( "versionToComparable( baseVersion ) =" + versionToComparable( baseVersion ) );
System.out.println( "versionToComparable( testVersion ) =" + versionToComparable( testVersion ) + " is this higher ?" );
return versionToComparable( testVersion ).compareTo( versionToComparable( baseVersion ) ) > 0;
}
//---- not worrying about += for something so small
private static String versionToComparable( String version )
{
// System.out.println("version - " + version);
String versionNum = version;
int at = version.indexOf( '-' );
if ( at >= 0 )
versionNum = version.substring( 0, at );
String[] numAr = versionNum.split( "\\." );
String versionFormatted = "0";
for ( String tmp : numAr )
{
versionFormatted += String.format( "%4s", tmp ).replace(' ', '0');
}
while ( versionFormatted.length() < 12 ) // pad out to aaaa.bbbb.cccc
{
versionFormatted += "0000";
}
// System.out.println( "converted min version =" + versionFormatted + "= : " + versionNum );
return versionFormatted + getVersionModifier( version, at );
}
//---- use order low to high: -xyz, -SNAPSHOT, -ALPHA, -BETA, -RC, -RELEASE/nothing returns: 0, 1, 2, 3, 4, 5
private static String getVersionModifier( String version, int at )
{
// System.out.println("version - " + version );
String[] wordModsAr = { "-SNAPSHOT", "-ALPHA", "-BETA", "-RC", "-RELEASE" };
if ( at < 0 )
return "." + wordModsAr.length + "00"; // make nothing = RELEASE level
int i = 1;
for ( String word : wordModsAr )
{
if ( ( at = version.toUpperCase().indexOf( word ) ) > 0 )
return "." + i + getSecondVersionModifier( version.substring( at + word.length() ) );
i++;
}
return ".000";
}
//---- add 2 chars for any number after first modifier. -rc2 or -rc-2 returns 02
private static String getSecondVersionModifier( String version )
{
System.out.println( "second modifier =" + version + "=" );
Matcher m = Pattern.compile("(.*?)(\\d+).*").matcher( version );
// if ( m.matches() )
// System.out.println( "match ? =" + m.matches() + "= m.group(1) =" + m.group(1) + "= m.group(2) =" + m.group(2) + "= m.group(3) =" + (m.groupCount() >= 3 ? m.group(3) : "x") );
// else
// System.out.println( "No match" );
return m.matches() ? String.format( "%2s", m.group(2) ).replace(' ', '0') : "00";
}
public static void main(String[] args)
{
checkVersion( "3.10.0", "3.4.0");
checkVersion( "5.4.2", "5.4.1");
checkVersion( "5.4.4", "5.4.5");
checkVersion( "5.4.9", "5.4.12");
checkVersion( "5.9.222", "5.10.12");
checkVersion( "5.10.12", "5.10.12");
checkVersion( "5.10.13", "5.10.14");
checkVersion( "6.7.0", "6.8");
checkVersion( "6.7", "2.7.0");
checkVersion( "6", "6.3.1");
checkVersion( "4", "4.0.0");
checkVersion( "6.3.0", "6");
checkVersion( "5.10.12-Alpha", "5.10.12-beTA");
checkVersion( "5.10.13-release", "5.10.14-beta");
checkVersion( "6.7.0", "6.8-snapshot");
checkVersion( "6.7.1", "6.7.0-release");
checkVersion( "6-snapshot", "6.0.0-beta");
checkVersion( "6.0-snapshot", "6.0.0-whatthe");
checkVersion( "5.10.12-Alpha-1", "5.10.12-alpha-2");
checkVersion( "5.10.13-release-1", "5.10.13-release2");
checkVersion( "10-rc42", "10.0.0-rc53");
}
private static void checkVersion(String baseVersion, String testVersion)
{
System.out.println( "baseVersion - " + baseVersion );
System.out.println( "testVersion - " + testVersion );
System.out.println( "isVersionHigher = " + isVersionHigher( baseVersion, testVersion ) );
System.out.println( "---------------");
}
}
一些输出：
---------------
baseVersion - 6.7
testVersion - 2.7.0
versionToComparable( baseVersion ) =0000600070000.500
versionToComparable( testVersion ) =0000200070000.500 is this higher ?
isVersionHigher = false
---------------
baseVersion - 6
testVersion - 6.3.1
versionToComparable( baseVersion ) =0000600000000.500
versionToComparable( testVersion ) =0000600030001.500 is this higher ?
isVersionHigher = true
---------------
baseVersion - 4
testVersion - 4.0.0
versionToComparable( baseVersion ) =0000400000000.500
versionToComparable( testVersion ) =0000400000000.500 is this higher ?
isVersionHigher = false
---------------
baseVersion - 6.3.0
testVersion - 6
versionToComparable( baseVersion ) =0000600030000.500
versionToComparable( testVersion ) =0000600000000.500 is this higher ?
isVersionHigher = false
---------------
baseVersion - 5.10.12-Alpha
testVersion - 5.10.12-beTA
second modifier ==
versionToComparable( baseVersion ) =0000500100012.200
second modifier ==
versionToComparable( testVersion ) =0000500100012.300 is this higher ?
second modifier ==
second modifier ==
isVersionHigher = true
---------------
baseVersion - 5.10.13-release
testVersion - 5.10.14-beta
second modifier ==
versionToComparable( baseVersion ) =0000500100013.500
second modifier ==
versionToComparable( testVersion ) =0000500100014.300 is this higher ?
second modifier ==
second modifier ==
isVersionHigher = true
---------------
baseVersion - 6.7.0
testVersion - 6.8-snapshot
versionToComparable( baseVersion ) =0000600070000.500
second modifier ==
versionToComparable( testVersion ) =0000600080000.100 is this higher ?
second modifier ==
isVersionHigher = true
---------------
baseVersion - 6.7.1
testVersion - 6.7.0-release
versionToComparable( baseVersion ) =0000600070001.500
second modifier ==
versionToComparable( testVersion ) =0000600070000.500 is this higher ?
second modifier ==
isVersionHigher = false
---------------
baseVersion - 6-snapshot
testVersion - 6.0.0-beta
second modifier ==
versionToComparable( baseVersion ) =0000600000000.100
second modifier ==
versionToComparable( testVersion ) =0000600000000.300 is this higher ?
second modifier ==
second modifier ==
isVersionHigher = true
---------------
baseVersion - 6.0-snapshot
testVersion - 6.0.0-whatthe
second modifier ==
versionToComparable( baseVersion ) =0000600000000.100
versionToComparable( testVersion ) =0000600000000.000 is this higher ?
second modifier ==
isVersionHigher = false
---------------
baseVersion - 5.10.12-Alpha-1
testVersion - 5.10.12-alpha-2
second modifier =-1=
versionToComparable( baseVersion ) =0000500100012.201
second modifier =-2=
versionToComparable( testVersion ) =0000500100012.202 is this higher ?
second modifier =-2=
second modifier =-1=
isVersionHigher = true
---------------
baseVersion - 5.10.13-release-1
testVersion - 5.10.13-release2
second modifier =-1=
versionToComparable( baseVersion ) =0000500100013.501
second modifier =2=
versionToComparable( testVersion ) =0000500100013.502 is this higher ?
second modifier =2=
second modifier =-1=
isVersionHigher = true
---------------
baseVersion - 10-rc42
testVersion - 10.0.0-rc53
second modifier =42=
versionToComparable( baseVersion ) =0001000000000.442
second modifier =53=
versionToComparable( testVersion ) =0001000000000.453 is this higher ?
second modifier =53=
second modifier =42=
isVersionHigher = true
---------------
答案 11 :(得分：1)
我使用utility for comparing versions约定在 Android平台上创建了简单的Semantic Versioning。因此它仅适用于格式为X.Y.Z（Major.Minor.Patch）的字符串，其中X，Y和Z为非负整数。您可以在GitHub上找到它。
方法 Version.compareVersions（String v1，String v2）比较两个版本字符串。如果版本相等，则返回0;如果版本v1在版本v2之前，则返回1;如果版本v1在版本v2之后，则返回-1;如果版本格式无效，则返回-2。
答案 12 :(得分：1)
对于我的项目，我使用我的公共版本库https://github.com/raydac/commons-version
它包含两个辅助类 - 解析版本（解析后的版本可以与另一个版本对象进行比较，因为它可比较）和VersionValidator允许检查某些表达式的版本，如!=ide-1.1.1,>idea-1.3.4-SNAPSHOT;<1.2.3
答案 13 :(得分：1)
@alex在Kotlin上的post
class Version(inputVersion: String) : Comparable<Version> {
var version: String
private set
override fun compareTo(other: Version) =
(split() to other.split()).let {(thisParts, thatParts)->
val length = max(thisParts.size, thatParts.size)
for (i in 0 until length) {
val thisPart = if (i < thisParts.size) thisParts[i].toInt() else 0
val thatPart = if (i < thatParts.size) thatParts[i].toInt() else 0
if (thisPart < thatPart) return -1
if (thisPart > thatPart) return 1
}
0
}
init {
require(inputVersion.matches("[0-9]+(\\.[0-9]+)*".toRegex())) { "Invalid version format" }
version = inputVersion
}
}
fun Version.split() = version.split(".").toTypedArray()
用法：
Version("1.2.4").compareTo(Version("0.0.5")) //return 1
答案 14 :(得分：1)
我现在做完了，问自己，这是对的吗？因为我之前从未找到过最干净的解决方案：
您只需要像以下示例一样拆分字符串版本（“ 1.0.0”）：
userVersion.split("\\.")
那么您将拥有：{“ 1”，“ 0”，“ 0”}
现在，使用我做的方法：
isUpdateAvailable(userVersion.split("\\."), latestVersionSplit.split("\\."));
方法：
/**
* Compare two versions
*
* @param userVersionSplit - User string array with major, minor and patch version from user (exemple: {"5", "2", "70"})
* @param latestVersionSplit - Latest string array with major, minor and patch version from api (example: {"5", "2", "71"})
* @return true if user version is smaller than latest version
*/
public static boolean isUpdateAvailable(String[] userVersionSplit, String[] latestVersionSplit) {
int majorUserVersion = Integer.parseInt(userVersionSplit[0]);
int minorUserVersion = Integer.parseInt(userVersionSplit[1]);
int patchUserVersion = Integer.parseInt(userVersionSplit[2]);
int majorLatestVersion = Integer.parseInt(latestVersionSplit[0]);
int minorLatestVersion = Integer.parseInt(latestVersionSplit[1]);
int patchLatestVersion = Integer.parseInt(latestVersionSplit[2]);
if (majorUserVersion <= majorLatestVersion) {
if (majorUserVersion < majorLatestVersion) {
return true;
} else {
if (minorUserVersion <= minorLatestVersion) {
if (minorUserVersion < minorLatestVersion) {
return true;
} else {
return patchUserVersion < patchLatestVersion;
}
}
}
}
return false;
}
等待任何反馈：）
答案 15 :(得分：0)
使用Java 8 Stream替换组件中的前导零。这段代码通过了interviewbit.com
上的所有测试public int compareVersion(String A, String B) {
List<String> strList1 = Arrays.stream(A.split("\\."))
.map(s -> s.replaceAll("^0+(?!$)", ""))
.collect(Collectors.toList());
List<String> strList2 = Arrays.stream(B.split("\\."))
.map(s -> s.replaceAll("^0+(?!$)", ""))
.collect(Collectors.toList());
int len1 = strList1.size();
int len2 = strList2.size();
int i = 0;
while(i < len1 && i < len2){
if (strList1.get(i).length() > strList2.get(i).length()) return 1;
if (strList1.get(i).length() < strList2.get(i).length()) return -1;
int result = new Long(strList1.get(i)).compareTo(new Long(strList2.get(i)));
if (result != 0) return result;
i++;
}
while (i < len1){
if (!strList1.get(i++).equals("0")) return 1;
}
while (i < len2){
if (!strList2.get(i++).equals("0")) return -1;
}
return 0;
}
答案 16 :(得分：0)
最简单的解决方案是使用字符串比较。删除不需要的点或字母，以防版本类似于 v1.0.1Beta 使用 Regex("[^0-9]") 并且您获得 1.0 和 1.0.1 等版本：
String ver1 = "10";
String ver2 = "101";
int res = ver1.compareTo(ver2);
System.out.println("res: "+res);
如果ver1在字典序上小于ver2，则返回负数，如果相等则返回0，如果ver1大于则返回正数.
compareTo() 方法按字典顺序比较两个字符串。
比较基于字符串中每个字符的 Unicode 值。
如果字符串等于另一个字符串，则该方法返回 0。如果字符串小于另一个字符串（更少字符），则返回小于 0 的值；如果字符串大于另一个字符串（更多字符），则返回大于 0 的值。
答案 17 :(得分：0)
由于此页面上没有答案能很好地处理混合文本，因此我制作了自己的版本：
import java.util.regex.Matcher;
import java.util.regex.Pattern;
class Main {
static double parseVersion(String v) {
if (v.isEmpty()) {
return 0;
}
Pattern p = Pattern.compile("^(\\D*)(\\d*)(\\D*)$");
Matcher m = p.matcher(v);
m.find();
if (m.group(2).isEmpty()) {
// v1.0.0.[preview]
return -1;
}
double i = Integer.parseInt(m.group(2));
if (!m.group(3).isEmpty()) {
// v1.0.[0b]
i -= 0.1;
}
return i;
}
public static int versionCompare(String str1, String str2) {
String[] v1 = str1.split("\\.");
String[] v2 = str2.split("\\.");
int i = 0;
for (; i < v1.length && i < v2.length; i++) {
double iv1 = parseVersion(v1[i]);
double iv2 = parseVersion(v2[i]);
if (iv1 != iv2) {
return iv1 - iv2 < 0 ? -1 : 1;
}
}
if (i < v1.length) {
// "1.0.1", "1.0"
double iv1 = parseVersion(v1[i]);
return iv1 < 0 ? -1 : (int)Math.ceil(iv1);
}
if (i < v2.length) {
double iv2 = parseVersion(v2[i]);
return - iv2 < 0 ? -1 : (int)Math.ceil(iv2);
}
return 0;
}
public static void main(String[] args) {
System.out.println("versionCompare(v1.0.0, 1.0.0)");
System.out.println(versionCompare("v1.0.0", "1.0.0")); // 0
System.out.println("versionCompare(v1.0.0b, 1.0.0)");
System.out.println(versionCompare("v1.0.0b", "1.0.0")); // -1
System.out.println("versionCompare(v1.0.0.preview, 1.0.0)");
System.out.println(versionCompare("v1.0.0.preview", "1.0.0")); // -1
System.out.println("versionCompare(v1.0, 1.0.0)");
System.out.println(versionCompare("v1.0", "1.0.0")); // 0
System.out.println("versionCompare(ver1.0, 1.0.1)");
System.out.println(versionCompare("ver1.0", "1.0.1")); // -1
}
}
但是，在需要将“ alpha”与“ beta”进行比较的情况下，它还是不够的。
答案 18 :(得分：0)
对于要根据版本号显示“强制更新警报”的人，我有以下建议。在比较Android当前应用程序版本和Firebase远程配置版本之间的版本时，可以使用此功能。这不完全是所提问题的答案，但这肯定会对某人有所帮助。
import java.util.List;
import java.util.ArrayList;
import java.util.Arrays;
public class Main
{
static String firebaseVersion = "2.1.3"; // or 2.1
static String appVersion = "2.1.4";
static List<String> firebaseVersionArray;
static List<String> appVersionArray;
static boolean isNeedToShowAlert = false;
public static void main (String[]args)
{
System.out.println ("Hello World");
firebaseVersionArray = new ArrayList<String>(Arrays.asList(firebaseVersion.split ("\\.")));
appVersionArray = new ArrayList<String>(Arrays.asList(appVersion.split ("\\.")));
if(appVersionArray.size() < firebaseVersionArray.size()) {
appVersionArray.add("0");
}
if(firebaseVersionArray.size() < appVersionArray.size()) {
firebaseVersionArray.add("0");
}
isNeedToShowAlert = needToShowAlert(); //Returns false
System.out.println (isNeedToShowAlert);
}
static boolean needToShowAlert() {
boolean result = false;
for(int i = 0 ; i < appVersionArray.size() ; i++) {
if (Integer.parseInt(appVersionArray.get(i)) == Integer.parseInt(firebaseVersionArray.get(i))) {
continue;
} else if (Integer.parseInt(appVersionArray.get(i)) > Integer.parseInt(firebaseVersionArray.get(i))){
result = false;
break;
} else if (Integer.parseInt(appVersionArray.get(i)) < Integer.parseInt(firebaseVersionArray.get(i))) {
result = true;
break;
}
}
return result;
}
}
您可以通过复制粘贴来运行此代码 https://www.onlinegdb.com/online_java_compiler
答案 19 :(得分：0)
public static void main(String[] args) {
String version1 = "1.0";
String version2 = "1.0.0";
String[] version1_splits = version1.split("\\.");
String[] version2_splits = version2.split("\\.");
int length = version1_splits.length >= version2_splits.length ? version1_splits.length : version2_splits.length;
int i=0;
for(;i<length;i++){
int version1_int = getValue(version1_splits,i);
int version2_int = getValue(version2_splits,i);
if(version1_int > version2_int){
System.out.println("version1 > version2");
break;
}
else if(version1_int < version2_int){
System.out.println("version2 > version1");
break;
}
else{
if(i == length-1)
System.out.println("version1 = version2");
}
}
}
private static int getValue(String[] version1_splits, int i) {
int temp;
try{
temp = Integer.valueOf(version1_splits[i]);
}
catch(IndexOutOfBoundsException e){
temp=0;
}
return temp;
}
答案 20 :(得分：0)
基于https://stackoverflow.com/a/27891752/2642478
class Version(private val value: String) : Comparable<Version> {
private val splitted by lazy { value.split("-").first().split(".").map { it.toIntOrNull() ?: 0 } }
override fun compareTo(other: Version): Int {
for (i in 0 until maxOf(splitted.size, other.splitted.size)) {
val compare = splitted.getOrElse(i) { 0 }.compareTo(other.splitted.getOrElse(i) { 0 })
if (compare != 0)
return compare
}
return 0
}
}
您可以这样使用：
System.err.println(Version("1.0").compareTo( Version("1.0")))
System.err.println(Version("1.0") < Version("1.1"))
System.err.println(Version("1.10") > Version("1.9"))
System.err.println(Version("1.10.1") > Version("1.10"))
System.err.println(Version("0.0.1") < Version("1"))
答案 21 :(得分：0)
也许有人会对我的解决方案感兴趣：
class Version private constructor(private val versionString: String) : Comparable<Version> {
private val major: Int by lazy { versionString.split(".")[0].toInt() }
private val minor: Int by lazy { versionString.split(".")[1].toInt() }
private val patch: Int by lazy {
val splitArray = versionString.split(".")
if (splitArray.size == 3)
splitArray[2].toInt()
else
0
}
override fun compareTo(other: Version): Int {
return when {
major > other.major -> 1
major < other.major -> -1
minor > other.minor -> 1
minor < other.minor -> -1
patch > other.patch -> 1
patch < other.patch -> -1
else -> 0
}
}
override fun equals(other: Any?): Boolean {
if (other == null || other !is Version) return false
return compareTo(other) == 0
}
override fun hashCode(): Int {
return major * minor * patch
}
companion object {
private fun doesContainsVersion(string: String): Boolean {
val versionArray = string.split(".")
return versionArray.size in 2..3
&& versionArray[0].toIntOrNull() != null
&& versionArray[1].toIntOrNull() != null
&& (versionArray.size == 2 || versionArray[2].toIntOrNull() != null)
}
fun from(string: String): Version? {
return if (doesContainsVersion(string)) {
Version(string)
} else {
null
}
}
}
}
用法：
val version1 = Version.from("3.2")
val version2 = Version.from("3.2.1")
version1 <= version2
答案 22 :(得分：0)
Version class import java.util.*;
import java.lang.module.ModuleDescriptor.Version;
class Main {
public static void main(String[] args) {
var versions = Arrays.asList(
"1.0.2",
"1.0.0-beta.2",
"1.0.0",
"1.0.0-beta",
"1.0.0-alpha.12",
"1.0.0-beta.11",
"1.0.1",
"1.0.11",
"1.0.0-rc.1",
"1.0.0-alpha.1",
"1.1.0",
"1.0.0-alpha.beta",
"1.11.0",
"1.0.0-alpha.12.ab-c",
"0.0.1",
"1.2.1",
"1.0.0-alpha"
);
versions.stream()
.map(Version::parse)
.sorted()
.forEach(System.out::println);
}
}
输出：
0.0.1
1.0.0-alpha
1.0.0-alpha.1
1.0.0-alpha.12
1.0.0-alpha.12.ab-c
1.0.0-alpha.beta
1.0.0-beta
1.0.0-beta.2
1.0.0-beta.11
1.0.0-rc.1
1.0.0
1.0.1
1.0.2
1.0.11
1.1.0
1.2.1
1.11.0
答案 23 :(得分：0)
我已经写了一个小的Java / Android库来比较版本号：https://github.com/G00fY2/version-compare
它的基本作用是：
public int compareVersions(String versionA, String versionB) {
String[] versionTokensA = versionA.split("\\.");
String[] versionTokensB = versionB.split("\\.");
List<Integer> versionNumbersA = new ArrayList<>();
List<Integer> versionNumbersB = new ArrayList<>();
for (String versionToken : versionTokensA) {
versionNumbersA.add(Integer.parseInt(versionToken));
}
for (String versionToken : versionTokensB) {
versionNumbersB.add(Integer.parseInt(versionToken));
}
final int versionASize = versionNumbersA.size();
final int versionBSize = versionNumbersB.size();
int maxSize = Math.max(versionASize, versionBSize);
for (int i = 0; i < maxSize; i++) {
if ((i < versionASize ? versionNumbersA.get(i) : 0) > (i < versionBSize ? versionNumbersB.get(i) : 0)) {
return 1;
} else if ((i < versionASize ? versionNumbersA.get(i) : 0) < (i < versionBSize ? versionNumbersB.get(i) : 0)) {
return -1;
}
}
return 0;
}
此代码段不提供任何错误检查或处理。此外，我的库还支持“ 1.2-rc”>“ 1.2-beta”之类的后缀。
答案 24 :(得分：0)
public int CompareVersions(String version1, String version2)
{
String[] string1Vals = version1.split("\\.");
String[] string2Vals = version2.split("\\.");
int length = Math.max(string1Vals.length, string2Vals.length);
for (int i = 0; i < length; i++)
{
Integer v1 = (i < string1Vals.length)?Integer.parseInt(string1Vals[i]):0;
Integer v2 = (i < string2Vals.length)?Integer.parseInt(string2Vals[i]):0;
//Making sure Version1 bigger than version2
if (v1 > v2)
{
return 1;
}
//Making sure Version1 smaller than version2
else if(v1 < v2)
{
return -1;
}
}
//Both are equal
return 0;
}
答案 25 :(得分：0)
我编写了一个名为MgntUtils的开源库，该库具有可用于String版本的实用程序。它可以正确比较它们，并与版本范围一起使用，等等。这是该库javadoc，请参见方法TextUtils.comapreVersions(...)。它已经被大量使用和测试。这是article，描述了库及其获取位置。它可以作为Maven artifact和github使用（带有源代码和javadoc）
答案 26 :(得分：0)
自己写了一个小功能。使用列表更简单
public static boolean checkVersionUpdate(String olderVerison, String newVersion) {
if (olderVerison.length() == 0 || newVersion.length() == 0) {
return false;
}
List<String> newVerList = Arrays.asList(newVersion.split("\\."));
List<String> oldVerList = Arrays.asList(olderVerison.split("\\."));
int diff = newVerList.size() - oldVerList.size();
List<String> newList = new ArrayList<>();
if (diff > 0) {
newList.addAll(oldVerList);
for (int i = 0; i < diff; i++) {
newList.add("0");
}
return examineArray(newList, newVerList, diff);
} else if (diff < 0) {
newList.addAll(newVerList);
for (int i = 0; i < -diff; i++) {
newList.add("0");
}
return examineArray(oldVerList, newList, diff);
} else {
return examineArray(oldVerList, newVerList, diff);
}
}
public static boolean examineArray(List<String> oldList, List<String> newList, int diff) {
boolean newVersionGreater = false;
for (int i = 0; i < oldList.size(); i++) {
if (Integer.parseInt(newList.get(i)) > Integer.parseInt(oldList.get(i))) {
newVersionGreater = true;
break;
} else if (Integer.parseInt(newList.get(i)) < Integer.parseInt(oldList.get(i))) {
newVersionGreater = false;
break;
} else {
newVersionGreater = diff > 0;
}
}
return newVersionGreater;
}
答案 27 :(得分：-1)
我喜欢@Peter Lawrey的想法，并且我把它扩展到了进一步的限制：
/**
* Normalize string array,
* Appends zeros if string from the array
* has length smaller than the maxLen.
**/
private String normalize(String[] split, int maxLen){
StringBuilder sb = new StringBuilder("");
for(String s : split) {
for(int i = 0; i<maxLen-s.length(); i++) sb.append('0');
sb.append(s);
}
return sb.toString();
}
/**
* Removes trailing zeros of the form '.00.0...00'
* (and does not remove zeros from, say, '4.1.100')
**/
public String removeTrailingZeros(String s){
int i = s.length()-1;
int k = s.length()-1;
while(i >= 0 && (s.charAt(i) == '.' || s.charAt(i) == '0')){
if(s.charAt(i) == '.') k = i-1;
i--;
}
return s.substring(0,k+1);
}
/**
* Compares two versions(works for alphabets too),
* Returns 1 if v1 > v2, returns 0 if v1 == v2,
* and returns -1 if v1 < v2.
**/
public int compareVersion(String v1, String v2) {
// Uncomment below two lines if for you, say, 4.1.0 is equal to 4.1
// v1 = removeTrailingZeros(v1);
// v2 = removeTrailingZeros(v2);
String[] splitv1 = v1.split("\\.");
String[] splitv2 = v2.split("\\.");
int maxLen = 0;
for(String str : splitv1) maxLen = Math.max(maxLen, str.length());
for(String str : splitv2) maxLen = Math.max(maxLen, str.length());
int cmp = normalize(splitv1, maxLen).compareTo(normalize(splitv2, maxLen));
return cmp > 0 ? 1 : (cmp < 0 ? -1 : 0);
}
希望它有所帮助。它通过了interviewbit和leetcode中的所有测试用例（需要在compareVersion函数中取消注释两行）。
轻松测试！
答案 28 :(得分：-1)
此代码尝试解决此类比较版本。
大多数版本说明符，例如＆gt; = 1.0，都是不言自明的。该 说明符〜＆gt;具有特殊意义，通过实例最佳显示。 〜＆GT; 2.0.3是 相同于＆gt; = 2.0.3且＆lt; 2.1。 〜＆GT; 2.1与＆gt; = 2.1并且＆lt; 3.0。
public static boolean apply(String cmpDeviceVersion, String reqDeviceVersion)
{
Boolean equal = !cmpDeviceVersion.contains(">") && !cmpDeviceVersion.contains(">=") &&
!cmpDeviceVersion.contains("<") && !cmpDeviceVersion.contains("<=") &&
!cmpDeviceVersion.contains("~>");
Boolean between = cmpDeviceVersion.contains("~>");
Boolean higher = cmpDeviceVersion.contains(">") && !cmpDeviceVersion.contains(">=") && !cmpDeviceVersion.contains("~>");
Boolean higherOrEqual = cmpDeviceVersion.contains(">=");
Boolean less = cmpDeviceVersion.contains("<") && !cmpDeviceVersion.contains("<=");
Boolean lessOrEqual = cmpDeviceVersion.contains("<=");
cmpDeviceVersion = cmpDeviceVersion.replaceAll("[<>=~]", "");
cmpDeviceVersion = cmpDeviceVersion.trim();
String[] version = cmpDeviceVersion.split("\\.");
String[] reqVersion = reqDeviceVersion.split("\\.");
if(equal)
{
return isEqual(version, reqVersion);
}
else if(between)
{
return isBetween(version, reqVersion);
}
else if(higher)
{
return isHigher(version, reqVersion);
}
else if(higherOrEqual)
{
return isEqual(version, reqVersion) || isHigher(version, reqVersion);
}
else if(less)
{
return isLess(version, reqVersion);
}
else if(lessOrEqual)
{
return isEqual(version, reqVersion) || isLess(version, reqVersion);
}
return false;
}
private static boolean isEqual(String[] version, String[] reqVersion)
{
String strVersion = StringUtils.join(version);
String strReqVersion = StringUtils.join(reqVersion);
if(version.length > reqVersion.length)
{
Integer diff = version.length - reqVersion.length;
strReqVersion += StringUtils.repeat(".0", diff);
}
else if(reqVersion.length > version.length)
{
Integer diff = reqVersion.length - version.length;
strVersion += StringUtils.repeat(".0", diff);
}
return strVersion.equals(strReqVersion);
}
private static boolean isHigher(String[] version, String[] reqVersion)
{
String strVersion = StringUtils.join(version);
String strReqVersion = StringUtils.join(reqVersion);
if(version.length > reqVersion.length)
{
Integer diff = version.length - reqVersion.length;
strReqVersion += StringUtils.repeat(".0", diff);
}
else if(reqVersion.length > version.length)
{
Integer diff = reqVersion.length - version.length;
strVersion += StringUtils.repeat(".0", diff);
}
return strReqVersion.compareTo(strVersion) > 0;
}
private static boolean isLess(String[] version, String[] reqVersion)
{
String strVersion = StringUtils.join(version);
String strReqVersion = StringUtils.join(reqVersion);
if(version.length > reqVersion.length)
{
Integer diff = version.length - reqVersion.length;
strReqVersion += StringUtils.repeat(".0", diff);
}
else if(reqVersion.length > version.length)
{
Integer diff = reqVersion.length - version.length;
strVersion += StringUtils.repeat(".0", diff);
}
return strReqVersion.compareTo(strVersion) < 0;
}
private static boolean isBetween(String[] version, String[] reqVersion)
{
return (isEqual(version, reqVersion) || isHigher(version, reqVersion)) &&
isLess(getNextVersion(version), reqVersion);
}
private static String[] getNextVersion(String[] version)
{
String[] nextVersion = new String[version.length];
for(int i = version.length - 1; i >= 0 ; i--)
{
if(i == version.length - 1)
{
nextVersion[i] = "0";
}
else if((i == version.length - 2) && NumberUtils.isNumber(version[i]))
{
nextVersion[i] = String.valueOf(NumberUtils.toInt(version[i]) + 1);
}
else
{
nextVersion[i] = version[i];
}
}
return nextVersion;
}
答案 29 :(得分：-1)
对于Scala，您可以使用我创建的库：https://github.com/kypeli/sversion
Version("1.2") > Version("1.1") // true
Version("1.2.1") > Version("1.1.2") // true
Version("1.1.1") == Version("1.1.1") // true
Version("1.1.1") > Version("1.1") // true
Version("1.1.0") == Version("1.1") // true
Version("1.1-RC2") > Version("1.1-RC1") // true
Version("1.1-RC1") > Version("1.1") // true
答案 30 :(得分：-2)
这是一个优化的实施：
public static final Comparator<CharSequence> VERSION_ORDER = new Comparator<CharSequence>() {
@Override
public int compare (CharSequence lhs, CharSequence rhs) {
int ll = lhs.length(), rl = rhs.length(), lv = 0, rv = 0, li = 0, ri = 0;
char c;
do {
lv = rv = 0;
while (--ll >= 0) {
c = lhs.charAt(li++);
if (c < '0' || c > '9')
break;
lv = lv*10 + c - '0';
}
while (--rl >= 0) {
c = rhs.charAt(ri++);
if (c < '0' || c > '9')
break;
rv = rv*10 + c - '0';
}
} while (lv == rv && (ll >= 0 || rl >= 0));
return lv - rv;
}
};
结果：
"0.1" - "1.0" = -1
"1.0" - "1.0" = 0
"1.0" - "1.0.0" = 0
"10" - "1.0" = 9
"3.7.6" - "3.7.11" = -5
"foobar" - "1.0" = -1
答案 31 :(得分：-2)
public class VersionComparator {
/* loop through both version strings
* then loop through the inner string to computer the val of the int
* for each integer read, do num*10+<integer read>
* and stop when stumbling upon '.'
* When '.' is encountered...
* see if '.' is encountered for both strings
* if it is then compare num1 and num2
* if num1 == num2... iterate over p1++, p2++
* else return (num1 > num2) ? 1 : -1
* If both the string end then compare(num1, num2) return 0, 1, -1
* else loop through the longer string and
* verify if it only has trailing zeros
* If it only has trailing zeros then return 0
* else it is greater than the other string
*/
public static int compareVersions(String v1, String v2) {
int num1 = 0;
int num2 = 0;
int p1 = 0;
int p2 = 0;
while (p1 < v1.length() && p2 < v2.length()) {
num1 = Integer.parseInt(v1.charAt(p1) + "");
num2 = Integer.parseInt(v2.charAt(p2) + "");
p1++;
p2++;
while (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) != '.' && v2.charAt(p2) != '.') {
if (p1 < v1.length()) num1 = num1 * 10 + Integer.parseInt(v1.charAt(p1) + "");
if (p2 < v2.length()) num2 = num2 * 10 + Integer.parseInt(v2.charAt(p2) + "");
p1++;
p2++;
}
if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.' && v2.charAt(p2) == '.') {
if ((num1 ^ num2) == 0) {
p1++;
p2++;
}
else return (num1 > num2) ? 1 : -1;
}
else if (p1 < v1.length() && p2 < v2.length() && v1.charAt(p1) == '.') return -1;
else if (p1 < v1.length() && p2 < v2.length() && v2.charAt(p2) == '.') return 1;
}
if (p1 == v1.length() && p2 == v2.length()) {
if ((num1 ^ num2) == 0) return 0;
else return (num1 > num2) ? 1 : -1;
}
else if (p1 == v1.length()) {
if ((num1 ^ num2) == 0) {
while (p2 < v2.length()) {
if (v2.charAt(p2) != '.' && v2.charAt(p2) != '0') return -1;
p2++;
}
return 0;
}
else return (num1 > num2) ? 1 : -1;
}
else {
if ((num1 ^ num2) == 0) {
while (p1 < v1.length()) {
if (v1.charAt(p1) != '.' && v1.charAt(p1) != '0') return 1;
p1++;
}
return 0;
}
else return (num1 > num2) ? 1 : -1;
}
}
public static void main(String[] args) {
System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
System.out.println(compareVersions("11.21.1.0.0.1.0", "11.23") ^ -1);
System.out.println(compareVersions("11.23", "11.23.0.0.0.1.0") ^ -1);
System.out.println(compareVersions("11.2", "11.23") ^ -1);
System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
System.out.println(compareVersions("1.21.1.0.0.1.0", "2.23") ^ -1);
System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
System.out.println(compareVersions("11.23.0.0.0.0.0", "11.23") ^ 0);
System.out.println(compareVersions("11.23", "11.21.1.0.0.1.0") ^ 1);
System.out.println(compareVersions("1.5.1.3", "1.5.1.3.0") ^ 0);
System.out.println(compareVersions("1.5.1.4", "1.5.1.3.0") ^ 1);
System.out.println(compareVersions("1.2.1.3", "1.5.1.3.0") ^ -1);
System.out.println(compareVersions("1.2.1.3", "1.22.1.3.0") ^ -1);
System.out.println(compareVersions("1.222.1.3", "1.22.1.3.0") ^ 1);
}
}
答案 32 :(得分：-3)
我的java解决方案
public int compareVersion(String version1, String version2) {
String[] first = version1.split("\\.");
String[] second = version2.split("\\.");
int len = first.length<=second.length? first.length:second.length;
// the loop runs for whichever is the short version of two strings
for(int i=0;i<len;i++){
int firstInt = Integer.parseInt(first[i]);
int secondInt = Integer.parseInt(second[i]);
if(firstInt<secondInt){
return -1;
}
else if(firstInt>secondInt){
return 1;
}
}
// below two condition check if the length are the not the same
//if first string length is short then start from after first string length and compare it with second string value. second string value is not zero that means it is greater.
if(first.length<second.length){
for(int i=first.length;i<second.length;i++){
int secondInt = Integer.parseInt(second[i]);
if(secondInt!=0){
return -1;
}
}
}
// similar logic as above just that first length is grater this time.
else if(first.length>second.length){
for(int i=second.length;i<first.length;i++){
int firstInt = Integer.parseInt(first[i]);
if(firstInt!=0){
return 1;
}
}
}
// return 0 if both string value is the same
return 0;
}