我希望在sql的帮助下创建Thu, 31 October 2013
之类的日期。我怎么浏览了很多文章并找到了这个article。在本文中,我发现一个函数可以生成具有特定格式的字符串。
供参考我包括此功能。
CREATE FUNCTION dbo.fnFormatDate (@Datetime DATETIME, @FormatMask VARCHAR(32))
RETURNS VARCHAR(32)
AS
BEGIN
DECLARE @StringDate VARCHAR(32)
SET @StringDate = @FormatMask
IF (CHARINDEX (‘YYYY’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘YYYY’,
DATENAME(YY, @Datetime))
IF (CHARINDEX (‘YY’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘YY’,
RIGHT(DATENAME(YY, @Datetime),2))
IF (CHARINDEX (‘Month’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘Month’,
DATENAME(MM, @Datetime))
IF (CHARINDEX (‘MON’,@StringDate COLLATE SQL_Latin1_General_CP1_CS_AS)>0)
SET @StringDate = REPLACE(@StringDate, ‘MON’,
LEFT(UPPER(DATENAME(MM, @Datetime)),3))
IF (CHARINDEX (‘Mon’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘Mon’,
LEFT(DATENAME(MM, @Datetime),3))
IF (CHARINDEX (‘MM’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘MM’,
RIGHT(’0′+CONVERT(VARCHAR,DATEPART(MM, @Datetime)),2))
IF (CHARINDEX (‘M’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘M’,
CONVERT(VARCHAR,DATEPART(MM, @Datetime)))
IF (CHARINDEX (‘DD’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘DD’,
RIGHT(’0′+DATENAME(DD, @Datetime),2))
IF (CHARINDEX (‘D’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘D’,
DATENAME(DD, @Datetime))
RETURN @StringDate
END
GO
– Microsoft SQL Server date format function test
– MSSQL formatting dates
SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YYYY’) – 01/03/2012
SELECT dbo.fnFormatDate (getdate(), ‘DD/MM/YYYY’) – 03/01/2012
SELECT dbo.fnFormatDate (getdate(), ‘M/DD/YYYY’) – 1/03/2012
SELECT dbo.fnFormatDate (getdate(), ‘M/D/YYYY’) – 1/3/2012
SELECT dbo.fnFormatDate (getdate(), ‘M/D/YY’) – 1/3/12
SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YY’) – 01/03/12
SELECT dbo.fnFormatDate (getdate(), ‘MON DD, YYYY’) – JAN 03, 2012
SELECT dbo.fnFormatDate (getdate(), ‘Mon DD, YYYY’) – Jan 03, 2012
SELECT dbo.fnFormatDate (getdate(), ‘Month DD, YYYY’) – January 03, 2012
SELECT dbo.fnFormatDate (getdate(), ‘YYYY/MM/DD’) – 2012/01/03
SELECT dbo.fnFormatDate (getdate(), ‘YYYYMMDD’) – 20120103
SELECT dbo.fnFormatDate (getdate(), ‘YYYY-MM-DD’) – 2012-01-03
– CURRENT_TIMESTAMP returns current system date and time in standard internal format
SELECT dbo.fnFormatDate (CURRENT_TIMESTAMP,‘YY.MM.DD’) – 12.01.03
GO
————
我只想按照我的要求制作出格式。我怎么能用功能来修改它呢,或者任何人都可以为此做出另一种解决方案。
答案 0 :(得分:3)
试试这个
DECLARE @dt DATETIME = getdate()
SELECT LEFT(DATENAME(weekday,@dt),3) + ', ' + DATENAME(day,@dt) + ' ' + DATENAME(month,@dt) + ' ' + DATENAME(year,@dt)