我正在从wav文件中读取值;只选择其中一些值并将它们写入另一个wav文件(为了从wav文件中删除静默期)。问题是,当我创建这个新的wav文件时,它有背景噪音(原始的wav文件中不存在)。我在这里添加了正在编写文件部分的代码部分:
private void writeToFile(String filePath) {
short nChannels = 1;
int sRate = 16000;
short bSamples = 16;
audioShorts = new short[size];
int nSamples = 0;
for(int i=0; i<size-1; i++) {
//audioShorts[i] = Short.reverseBytes((short)(zff[i]*0x8000));
if(slope[i] >= slopeThreshold) { // Voice region -- Should be written to output
audioShorts[nSamples] = Short.reverseBytes((short)(a[i]*0x8000));
audioShorts[nSamples+1] = Short.reverseBytes((short)(a[i+1]*0x8000));
nSamples += 2;
i++;
}
/*else
audioShorts[i] = 0;*/
}
finalShorts = new short[nSamples];
for(int i=0; i<nSamples; i++){
finalShorts[i] = audioShorts[i];
}
data = new byte[finalShorts.length*2];
ByteBuffer buffer = ByteBuffer.wrap(data);
ShortBuffer sbuf = buffer.asShortBuffer();
sbuf.put(finalShorts);
data = buffer.array();
Log.d("Data length------------------------------", Integer.toString(data.length));
RandomAccessFile randomAccessWriter;
try {
randomAccessWriter = new RandomAccessFile(filePath, "rw");
randomAccessWriter.setLength(0); // Set file length to 0, to prevent unexpected behaviour in case the file already existed
randomAccessWriter.writeBytes("RIFF");
randomAccessWriter.writeInt(Integer.reverseBytes(36+data.length)); // File length
randomAccessWriter.writeBytes("WAVE");
randomAccessWriter.writeBytes("fmt ");
randomAccessWriter.writeInt(Integer.reverseBytes(16)); // Sub-chunk size, 16 for PCM
randomAccessWriter.writeShort(Short.reverseBytes((short) 1)); // AudioFormat, 1 for PCM
randomAccessWriter.writeShort(Short.reverseBytes(nChannels));// Number of channels, 1 for mono, 2 for stereo
randomAccessWriter.writeInt(Integer.reverseBytes(sRate)); // Sample rate
randomAccessWriter.writeInt(Integer.reverseBytes(sRate*bSamples*nChannels/8)); // Byte rate, SampleRate*NumberOfChannels*BitsPerSample/8
randomAccessWriter.writeShort(Short.reverseBytes((short)(nChannels*bSamples/8))); // Block align, NumberOfChannels*BitsPerSample/8
randomAccessWriter.writeShort(Short.reverseBytes(bSamples)); // Bits per sample
randomAccessWriter.writeBytes("data");
randomAccessWriter.writeInt(Integer.reverseBytes(data.length)); // No. of samples
randomAccessWriter.write(data);
randomAccessWriter.close();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
答案 0 :(得分:0)
您的代码段会遗漏一些详细信息(例如slope和slopeThreshold),因此请将此答案视为建议。
通常,这种音频数据的斩波会引入噪音。这取决于切割发生的位置。如果切割前的最后一个样本与之后的第一个样本相同,那么您是安全的,否则您将引入一次点击。
如果切割不频繁,您将听到单击,但如果斩波经常发生,则可能听起来像连续的噪音。
要在没有点击的情况下执行此操作,您需要在每次剪切周围添加淡出淡出和淡入淡出。
编辑:尝试删除“if(slope [i]&gt; = slopeThreshold)”条件并查看噪音是否消失。如果是这样,噪音很可能是我所描述的结果。否则,您可能会遇到各种字节转换错误。
答案 1 :(得分:0)
而不是:
data = new byte[finalShorts.length*2];
ByteBuffer buffer = ByteBuffer.wrap(data);
ShortBuffer sbuf = buffer.asShortBuffer();
sbuf.put(finalShorts);
data = buffer.array();
是否有必要将short []转换为byte []?
data = shortToBytes(finalShorts);
public byte [] shortToBytes(short [] input){
int short_index, byte_index;
int iterations = input.length;
byte [] buffer = new byte[input.length * 2];
short_index = byte_index = 0;
for(/*NOP*/; short_index != iterations; /*NOP*/)
{
buffer[byte_index] = (byte) (input[short_index] & 0x00FF);
buffer[byte_index + 1] = (byte) ((input[short_index] & 0xFF00) >> 8);
++short_index; byte_index += 2;
}
return buffer;
}
这项工作适合我。