所以我有这个充满名字的链表。用户将搜索名称的第一个字母,并打印出名称以字母开头的节点。我跑的时候以为我没有收到任何回复。如果我在循环中插入一些打印线,我会回来的。
这是:
public String printSection(){
LinkedListNode current = front;
String searchedLetter;
int i = 0;
String retSec = "The nodes in the list are:\n";
//Get the input of the name being removed
Scanner s = new Scanner(System.in);
System.out.println("Enter the first letter of the section you would like to print out");
searchedLetter = s.nextLine();
//while current is not null
while(current != null){
//if the data in current starts with the letter entered for searchedLetter
if(current.getData().startsWith(searchedLetter)){
//if(current.getData().substring(0,1) == searchedLetter){
//Increment the number of the node
i++;
//Print the node(s)
retSec += "Node " + i + " is: " + current.getData() + "\n";
//Traverse the list
current = current.getNext();
System.out.println("You made it here");
}
}
return retSec;
}
}
这是:(新的工作方法)
public void printSection(){
LinkedListNode current = front;
String searchedLetter;
int i = 0;
//Get the input of the name being removed
Scanner s = new Scanner(System.in);
System.out.println("Enter the first letter of the section you would like to print out");
searchedLetter = s.nextLine();
//while current is not null
while(current != null){
//if the data in current starts with the letter entered for searchedLetter
if(current.getData().startsWith(searchedLetter)){
//Increment the number of the node
i++;
//Print the node
System.out.println("Node " + i + " is: " + current.getData());
}
//Traverse the list
current = current.getNext();
}
}
答案 0 :(得分:2)
你在这里遇到了无限循环。
你只需要一个while循环,你必须跳转到列表中的下一个元素,无论元素是否以搜索到的字母开头。
重新编写if语句并删除第二个while循环。另外,请务必始终转到下一个元素。
编辑:深入了解您的代码我意识到您也没有检查用户提出的输入。他实际上不限于单个字符,但可以输入整行文本。所以要么修复你给他的解释,要么引入你的输入验证(如果输入无效,包括一些错误信息)。