Question

请看一下： -

 public static ArrayList<ContactsEntityBean> getContactDetails(
            Context mContext) {
        ArrayList<ContactsEntityBean> contactList = new ArrayList<ContactsEntityBean>();
        ContentResolver cr = mContext.getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                null, null, null);
        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur
                        .getColumnIndex(ContactsContract.Contacts._ID));
                Cursor cur1 = cr.query(
                        ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                        null, ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                + " = ?", new String[] {
                            id
                        }, null);
                while (cur1.moveToNext()) {
                    ContactsEntityBean contactsEntityBean = new ContactsEntityBean();
                    // to get the contact names
                    String name = cur1
                            .getString(cur1
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

                    // Log.e("Name :", name);
                    String email = cur1
                            .getString(cur1
                                    .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));

                    // Log.e("Email", email);
                    contactsEntityBean.setName(name);
                    contactsEntityBean.setEmail(email);
                    if (email != null) {
                        contactList.add(contactsEntityBean);
                    }
                }
                cur1.close();
            }
        }
        return contactList;
    }

这个方法是从同一个用户返回多个联系人，假如我已经为同一个用户存储了abc @ gmail.com，abc @ gmail.com，那么它返回abc@gmail.com& abc@gmail.com 但我只想要一个记录abc@gmail.com

 public static ArrayList<SearchEntityBean> getContactEmailDetails(
            Context mContext) {
        ArrayList<SearchEntityBean> contactList = new ArrayList<SearchEntityBean>();


        try {
            ContentResolver cr = mContext.getContentResolver();
            Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
                    null, null, null);
            if (cur.getCount() > 0) {
                while (cur.moveToNext()) {
                    String email = "";
                    String id = cur.getString(cur
                            .getColumnIndex(ContactsContract.Contacts._ID));

                    Cursor cur1 = cr.query(
                            ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                            null,
                            ContactsContract.CommonDataKinds.Email.CONTACT_ID
                                    + " = ?", new String[] {
                                id
                            }, null);
                    SearchEntityBean contactsEntityBean = new SearchEntityBean();
                    while (cur1.moveToNext()) {

                        // to get the contact names

                        String name = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                        String image = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_ID));
                        String mail = cur1
                                .getString(cur1
                                        .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));

                        if (mail != null) {
                            if (!mail.equalsIgnoreCase(LoginPreferenceClass
                                    .getEmailID(mContext)))
                                email = email + mail + ",";
                        }
                        // Log.e("rohit", "Contact  Email :" + email);
                        contactsEntityBean.setName(name);
                        contactsEntityBean.setImage(image);

                    }

                    if (email != null) {

                        if (email.length() > 0) {

                            if (email.split(",").length > 1) {

                                contactsEntityBean.setMutipleEmail(true);

                            }

                            contactsEntityBean.setUserType("2");
                            contactsEntityBean.setContactId(id);
                            contactsEntityBean.setEmail(email);
                            contactList.add(contactsEntityBean);
                        }
                    }
                    cur1.close();
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
        HashSet<SearchEntityBean> hs = new HashSet<SearchEntityBean>();
        hs.addAll(contactList);
        contactList.clear();
        contactList.addAll(hs);
        return contactList;
    }

Answer 1

您应该修改ContactsEntityBean，如下所示

public class ContactsEntityBean {
    private HashSet<String> emails = new HashSet<String>(); 

    public void setEmail(String email) {
        if (email == null)
            return; 
        this.emails.add(email.trim()); 
    }

    public HashSet<String> getEmails() {
        return this.emails; 
    }
}

将关注重复的电子邮件......您可以对地址，电话等使用相同的逻辑。

将您的ContactsEntityBean替换为以下代码

public class ContactsEntityBean {
    private HashSet<String> emails;
    private HashSet<String> phones;
    private HashSet<String> addresses;
    private String contactId;
    private boolean checked = false;

    public ContactsEntityBean() {
        this.emails = new HashSet<String>();
        this.phones = new HashSet<String>();
        this.addresses = new HashSet<String>();
    }

    public HashSet<String> getPhones() {
        return phones;
    }

    public void setPhones(String phone) {
        if (phone == null)
            return;
        this.phones.add(phone.trim());
    }

    public HashSet<String> getAddresses() {
        return addresses;
    }

    public void setAddresses(String address) {
        if (address == null)
            return;
        this.addresses.add(address.trim());
    }

    public void setEmails(String email) {
        if (email == null)
            return;
        this.emails.add(email.trim());
    }

    public HashSet<String> getEmails() {
        return emails;
    }

    public String getContactId() {
        return contactId;
    }

    public void setContactId(String contactId) {
        this.contactId = contactId;
    }

    public boolean isChecked() {
        return checked;
    }

    public void setChecked(boolean checked) {
        this.checked = checked;
    }
}

无需关心重复。这将关心所有的事情..

Answer 2

这是我的工作

private void getContactDetails(ContentResolver contentResolver) {

        Cursor phones = contentResolver.query(
                ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null,
                null, null);
        HashSet<String> mobileNoSet = new HashSet<String>();

        while (phones.moveToNext()) {
            String name = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
            String phoneNumber = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            String email = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Email.ADDRESS));
            String imagUri = phones
                    .getString(phones
                            .getColumnIndex(ContactsContract.CommonDataKinds.Photo.PHOTO_URI));
            long id = phones.getColumnIndex(ContactsContract.Contacts._ID);

            if (!mobileNoSet.contains(phoneNumber)) {
                arrayContacts.add(new Contact(name, phoneNumber, email,
                        imagUri, id));
                mobileNoSet.add(phoneNumber);
            }
        }

        adapterContact = new AdapterContact(getActivity(), arrayContacts);
        listContact.setAdapter(adapterContact);
    }

Answer 3

通过改变你这样的方法你可以获得唯一一个不重复的联系人。

public static ArrayList<ContactsEntityBean> getContactDetails(Context mContext) {
    ArrayList<ContactsEntityBean> contactList = new ArrayList<ContactsEntityBean>();
    ContentResolver cr = mContext.getContentResolver();
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
            null, null, null);
    HashMap<String, String> data = new HashMap<String, String>();
    if (cur.getCount() > 0) {
        while (cur.moveToNext()) {
            String id = cur.getString(cur
                    .getColumnIndex(ContactsContract.Contacts._ID));
            Cursor cur1 = cr.query(
                    ContactsContract.CommonDataKinds.Email.CONTENT_URI,
                    null, ContactsContract.CommonDataKinds.Email.CONTACT_ID
                            + " = ?", new String[] { id }, null);
            while (cur1.moveToNext()) {
                ContactsEntityBean contactsEntityBean = new ContactsEntityBean();
                // to get the contact names
                String name = cur1
                        .getString(cur1
                                .getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));

                // Log.e("Name :", name);
                String email = cur1
                        .getString(cur1
                                .getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
                if (!data.containsValue(email)) {
                    // Log.e("Email", email);
                    contactsEntityBean.setName(name);
                    contactsEntityBean.setEmail(email);
                   data.put(name, email);
                    if (email != null) {
                        contactList.add(contactsEntityBean);
                    }
                }


            }
            cur1.close();
        }
    }
    return contactList;
}

Answer 4

将联系人保存在ArrayList 中，然后从列表中删除重复项。删除重复元素的最简单方法是将内容添加到Set（不允许重复），然后将Set添加回ArrayList。

像这样使用HashSet。

ArrayList al = new ArrayList();
// add elements to al, including duplicates
HashSet hs = new HashSet();
hs.addAll(al);
al.clear();
al.addAll(hs);

Answer 5

使用HashMap是因为HashMap不允许重复的键

声明全局变量

// Hash Maps
Map<String, String> nameEmailMap = new HashMap<String, String>();

在循环中将数据添加到HashMap

// Enter Into Hash Map
nameEmailMap.put(email, name);

循环外获取日志

// Get The Contents of Hash Map in Log
        for (Map.Entry<String, String> entry : namePhoneMap.entrySet()) {
            String key = entry.getKey();
            Log.d(TAG, "Phone :" + key);
            String value = entry.getValue();
            Log.d(TAG, "Name :" + value);
        }

有关如何检索不重复的联系人的完整答案，请参阅https://stackoverflow.com/a/54227282/3904109（对于电子邮件）和https://stackoverflow.com/a/54228199/3904109（对于电话）

Answer 6

此解决方案将：

删除重复项
删除所有不必要的开头，即当前仅允许数字以03、92和+92开头

显示所有同名电话，例如John有2个电话号码。

 fun fetchContacts(): List<UserObject> {\
          val contacts: ArrayList<UserObject> = ArrayList()
          val mobileNoSet = HashSet<String>()
          val cursor= requiredContext()?.contentResolver?.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,arrayOf(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,ContactsContract.CommonDataKinds.Phone.NUMBER,ContactsContract.CommonDataKinds.Phone.PHOTO_URI),null,null,"DISPLAY_NAME ASC")

    while (cursor!!.moveToNext()) {
         val index = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)
         val numberIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)
         val photoIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI)
         val strName = cursor.getString(index)
         var number = cursor.getString(numberIndex)
         number = number.replace(" ", "")
         val photo = cursor.getString(photoIndex)
         if ((number.startsWith("03") || number.startsWith("92")||number.startsWith("+92")) && !mobileNoSet.contains(number)) {
                contacts.add(UserObject(photo,strName,number))mobileNoSet.add(number)
            }
     }
    return contacts
  }

Answer 7

在您的ArrayList中添加联系电子邮件后，在continue之后添加HashSet并使用if (email != null) { contactList.add(contactsEntityBean); continue; }而不是ArrayList

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如何从android中的联系人列表中删除重复的联系人

7 个答案: