在我的应用程序中，我需要将图像和注释（180个文本）字符发送到服务器。
现在可以单独发送图像和文本，但我现在需要一起发送。
方法是什么？
目前正在使用线程发送图片。
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(
sourceFile);
URL url = new URL(
"http://xxx.com/image.php");
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("uploaded_file", fileName);
// conn.setRequestProperty("id", imei);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=uploaded_file; filename="
+ fileName + imei + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
runOnUiThread(new Runnable() {
public void run() {
Toast.makeText(getBaseContext(),
"File Upload Complete.", Toast.LENGTH_SHORT)
.show();
File delfile = new File(currentfile);
//delfile.delete();
}
});
}
// close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
// dialog.dismiss();
ex.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
// messageText.setText("MalformedURLException Exception : check script url.");
Toast.makeText(getBaseContext(),
"MalformedURLException", Toast.LENGTH_SHORT)
.show();
}
});
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
// dialog.dismiss();
e.printStackTrace();
runOnUiThread(new Runnable() {
public void run() {
// messageText.setText("Got Exception : see logcat ");
Toast.makeText(getBaseContext(),
"upload failed Please, try after some time ",
Toast.LENGTH_SHORT).show();
}
});
Log.e("Upload file to server Exception",
"Exception : " + e.getMessage(), e);
}
// dialog.dismiss();
return serverResponseCode;
} // End else block
使用简单的http post方法发送文本。
我需要这个用于我的应用程序，我们将拍摄快照并在edittext框中键入一些内容并发送。
答案 0 :(得分：5)
首先，您需要此org.apache.httpcomponents.httpclient_4.2.1 jar文件并导入到您的构建路径。
你可以这样做。请考虑以下
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONException;
import org.json.JSONObject;
宣言：
private List<NameValuePair> nameValuePairs;
private HttpURLConnection connection = null;
private DataOutputStream outputStream = null;
private String lineEnd = "\r\n";
private String twoHyphens = "--";
private String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
源代码如下：
try {
FileInputStream fileInputStream = new FileInputStream(StickerToSend);
URL url = new URL("Your URL");
connection = (HttpURLConnection) url.openConnection();
// Allow Inputs & Outputs
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
// Enable POST method
connection.setRequestMethod("POST");
connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
outputStream = new DataOutputStream(connection.getOutputStream());
// ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
// Here you can add parameters as follows :
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
// The keyword "type" is the key value and
outputStream
.writeBytes("Content-Disposition: form-data; name=\"type\""
+ lineEnd);
outputStream.writeBytes(lineEnd);
// You can assign values as like follows :
outputStream.writeBytes("Your value");
outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
outputStream
.writeBytes("Content-Disposition: form-data; name=\"sticker\";filename=\""
+ StickerToSend + "\"" + lineEnd);
outputStream.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// Read file
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
outputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + twoHyphens
+ lineEnd);
// int serverResponseCode = connection.getResponseCode();
String serverResponseMessage = connection.getResponseMessage();
Log.d("The server response message ", " Server Response"
+ serverResponseMessage);
fileInputStream.close();
outputStream.flush();
// ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
InputStream is = connection.getInputStream();
// retrieve the response from server
int ch;
StringBuffer b = new StringBuffer();
while ((ch = is.read()) != -1) {
b.append((char) ch);
}
String result = b.toString();
Log.i("Response", result);
JSONObject jsonobject;
try {
jsonobject = new JSONObject(result);
boolean isPosted = jsonobject.getJSONObject("response")
.getString("httpCode").equals("200") ? true : false;
if (isPosted)
mHandler.sendEmptyMessage(POST_SUCCESS);
else
mHandler.sendEmptyMessage(POST_FAILURE);
} catch (JSONException e) {
Log.d("the xceptions ",
"Xcep in posting status messages are : "
+ e.getMessage());
}
outputStream.close();
} catch (Exception e) {
Log.d("Xceptions",
"Xceptions are upload video file " + e.getMessage());
}
这段代码确实非常有效。我也检查了这个。如果有任何问题，请随意。
答案 1 :(得分：0)
您可以使用base64编码器将图像编码为字符串（Base 64 encode and decode example code）并创建Web服务以将其发送到服务器。因此，在该Web服务中，您可以添加多个输入
答案 2 :(得分：0)
试试这可能有助于你
public void WSCall(final String filePath, final String textTosend) {
try {
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://xxx.com/image.php");
StringBody data = new StringBody(textTosend, Charset.forName(HTTP.UTF_8));
MultiPartEntity entity = new MultiPartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
entity.addPart("uploaded_file", new FileBody(new File(filePath), "image/png"));
entity.addPart("text", data);
httppost.setEntity(entity);
HttpResponse WSresponse = httpclient.execute(httppost);
} catch (Throwable e) {
}
}