是否可以在模型中使用Codeigniter Email类?
我一直在尝试,但它拒绝加载邮件对象。通常,是否允许将库加载到模型中?
代码
类ClubInvitation扩展了DataMapper {
var $table = "club_invitations";
var $has_one = array("club");
public function __construct($id){
parent::__construct($id);
$this->load->library('email');
}
public function inviteEmailToClub($email, $club, $message){
$invite = new ClubInvitation();
$invite->email = $email;
$invite->code = random_string('unique', null);
//$invite->save($club);
$club->ClubAdmin->limit(1);
$mainClubAdmin = $club->ClubAdmin->get()->User->get();
$data['club'] = $club;
$data['message'] = $message;
$data['club_leader'] = $mainClubAdmin;
$data['invite_code'] = $invite->code;
$email_body = $this->WBLayout->emailTemplate('invited_to_club', $data);
$this->email->from($mainClubAdmin->User->getAccount()->email, $club->name);
$this->email->to($email);
$this->email->subject($club->name.' has invited you to join');
$this->email->message($email_body);
$this->email->send();
}
}
答案 0 :(得分:2)
通常,库被加载到控制器中并从那里访问,而不是从模型中访问。您可以将模型中的数据数组返回到控制器,并使用控制器本身的电子邮件库。如果这对您不可行,那么请尝试:
public function __construct($id){
parent::__construct($id);
}
public function inviteEmailToClub($email, $club, $message){
$CI =& get_instance();
$CI->load->library('email');
.....
$CI->email->from($mainClubAdmin->User->getAccount()->email, $club->name);
....
}