这是经过评估的工作,所以请不要直截了当地回答。
我的程序应该计算用户等级:“通过”,“失败”或“通过补偿”。但是,它没有回答答案。我无法弄清楚为什么 - 有人可以帮忙吗?
公共类MarkCalculator { static int [] marks = new int [12];
//public static Scanner keyboard = new Scanner(System.in);
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
int weighting;
int coursework;
int exammark;
System.out.println("Please enter course work weighting");
marks[0]= kb.nextInt();
System.out.println("Please enter course work mark");
marks[1]= kb.nextInt();
System.out.println("Please enter exam mark");
marks[2]= kb.nextInt();
MarkCalculator mc = new MarkCalculator();
mc.computeMarks(marks);
}
public String[] computeMarks(int[] marks) {
final int[] WEIGHTING = {55,66,55,44,33,44};
String[] results = new String[WEIGHTING.length];
for (int i = 0; i < marks.length / 2; i++) {
int exam = marks[i];
int cw = marks[i];
int weight = WEIGHTING[i];
int formula = ((cw + weight) + (exam * (100 - weight)) / 100);
if (formula >= 40){
results[i]="PASS";
} else if ((formula < 39) && (formula > 35)){
results[i]="COMPENSATION PASS";
}else{
results[i]="FAIL";
}
}
return results;
}
}
答案 0 :(得分:3)
final int[] WEIGHTING = {};
String[] results = new String[WEIGHTING.length];
这是一个问题。加权没有初始尺寸。
答案 1 :(得分:1)
另外:你没有用任何东西初始化标记。试试这个:
System.out.println("Please enter course work weighting");
marks[0]= kb.nextInt();
System.out.println("Please enter course work mark");
marks[1]= kb.nextInt();
System.out.println("Please enter exam mark");
marks[2]= kb.nextInt();
MarkCalculator mc = new MarkCalculator();
mc.computeMarks(marks);
答案 2 :(得分:1)
问题是加权是空的
final int[] WEIGHTING = {}; // empty
String[] results = new String[WEIGHTING.length];
for (int i = 0; i < marks.length / 2; i++) {
int exam = marks[i];
int cw = marks[i];
int weight = WEIGHTING[i]; // You cant access elements from an empty array
另外
MarkCalculator mc = new MarkCalculator();
mc.computeMarks(marks);
这里你传递的标记是空的。
修改强>
您的程序无法正常工作的原因是因为您没有从computeMarks中获取结果。你应该将它存储在像
这样的main中的数组中String[] result = mc.computeMarks(marks);
for(int k=0;k<result.length;k++)
{
System.out.println(result[k]);
}