我的数据库中有两个表。一个名为jokes
,另一个名为category
。
jokes
CREATE TABLE `jokes` (
`joke_id` int(11) NOT NULL AUTO_INCREMENT,
`joke` varchar(1024) NOT NULL,
`category_id` int(11) NOT NULL,
PRIMARY KEY (`joke_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=9 ;
category
CREATE TABLE `category` (
`category_id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(51) NOT NULL,
PRIMARY KEY (`category_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
我的PHP在表格中显示笑话
<?php
include 'database.php';
$pdo = Database::connect();
$sql = 'SELECT * FROM jokes ORDER BY joke_id DESC';
foreach ($pdo->query($sql) as $row) {
echo '';
echo '<table class="table">';
echo '<thead>';
echo '<tr>';
echo '<h3><th>Category Name</th></h3>';
echo '<h3><th>Action</th></h3>';
echo '<tbody>';
echo '<tr>';
echo '<thead>';
echo '<tbody>';
echo '<tr>';
echo '<td >' . $row['joke'] . '</td>';
echo '<td width=250>';
echo '<a class="btn-big white" href="read.php?id=' . $row['joke_id'] . '">Read</a>';
echo ' ';
echo '<a class="btn-big green" href="update.php?id=' . $row['joke_id'] . '">Update</a>';
echo ' ';
echo '<a class="btn-big red" href="delete.php?id=' . $row['joke_id'] . '">Delete</a>';
echo '</td>';
echo '</tr>';
}
Database::disconnect();
?>
我的问题是如何通过PHP在echo category_name
中显示笑话的'<h3><th>Category name</th></h3>';
?因为目前,该表只显示一个笑话,没有笑话的类别名称。例如:Celebrity Joke:这是一个名人笑话。
答案 0 :(得分:1)
您应该更改查询以包含类别名称。
SELECT j.joke AS joke, j.joke_id AS joke_id, c.name AS category
FROM jokes j, category c
WHERE j.category_id = c.category_id
之后,您可以致电$row['category']
答案 1 :(得分:0)
使用此查询:
$sql = 'SELECT j.*, c.name
FROM jokes j
LEFT JOIN category c ON c.category_id = j.category_id
ORDER BY joke_id DESC';
要回显类别名称,请使用:$row['name']