Question

$days = $days_of_week[2];

if (date('d/m/Y') == $days) {
    $today = "Correct";
} else if (date('d/m/Y') != $days) {
    $today = '<br>Non correct<br>';
    $today1 = date('d/m/Y');
    $today2 = $days_of_week[2];
}

当我回复$today，$today1和$today2时会返回。

非正确06/11/2013 06/11/2013

我在这里遗漏了什么吗？试过===

Answer 1

尝试将第一个字符串更改为

$days = trim($days_of_week[2]);

可能在您的输入中是任何“隐形”符号。例如任何空格

Answer 2

试试这个：

$days = $days_of_week[2];

if (date('d/m/Y') == date('d/m/Y', strtotime($days))) {
  $today = "Correct";
} else if (date('d/m/Y') != date('d/m/Y', strtotime($days))) {
  $today = '<br>Non correct<br>';
  $today1 = date('d/m/Y');
  $today2 = $days_of_week[2];
}

这个日期比较怎么不相等？

2 个答案: