我正在尝试使用 php echo $ _SERVER ['PHP_SELF']; 向自己提交页面,但仍然收到以下错误:您的SQL语法中有错误;检查与MySQL服务器版本对应的手册,以便在第1行的''附近使用正确的语法 ....
页面上有不同的表单,我遇到了同样的问题。
可能是问题的根源是什么?
<?php
require_once('Connections/speedycms.php');
$client_id = mysql_real_escape_string($_GET['id']);
if (!isset($_SESSION)) {
session_start();
}
$MM_authorizedUsers = "";
$MM_donotCheckaccess = "true";
// *** Restrict Access To Page: Grant or deny access to this page
function isAuthorized($strUsers, $strGroups, $UserName, $UserGroup) {
// For security, start by assuming the visitor is NOT authorized.
$isValid = False;
// When a visitor has logged into this site, the Session variable MM_Username set equal to their username.
// Therefore, we know that a user is NOT logged in if that Session variable is blank.
if (!empty($UserName)) {
// Besides being logged in, you may restrict access to only certain users based on an ID established when they login.
// Parse the strings into arrays.
$arrUsers = Explode(",", $strUsers);
$arrGroups = Explode(",", $strGroups);
if (in_array($UserName, $arrUsers)) {
$isValid = true;
}
// Or, you may restrict access to only certain users based on their username.
if (in_array($UserGroup, $arrGroups)) {
$isValid = true;
}
if (($strUsers == "") && true) {
$isValid = true;
}
}
return $isValid;
}
$MM_restrictGoTo = "login.php";
if (!((isset($_SESSION['MM_Username'])) && (isAuthorized("",$MM_authorizedUsers, $_SESSION['MM_Username'], $_SESSION['MM_UserGroup'])))) {
$MM_qsChar = "?";
$MM_referrer = $_SERVER['PHP_SELF'];
if (strpos($MM_restrictGoTo, "?")) $MM_qsChar = "&";
if (isset($QUERY_STRING) && strlen($QUERY_STRING) > 0)
$MM_referrer .= "?" . $QUERY_STRING;
$MM_restrictGoTo = $MM_restrictGoTo. $MM_qsChar . "accesscheck=" . urlencode($MM_referrer);
header("Location: ". $MM_restrictGoTo);
exit;
}
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
if (PHP_VERSION < 6) {
$theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
}
$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);
switch ($theType) {
case "text":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "long":
case "int":
$theValue = ($theValue != "") ? intval($theValue) : "NULL";
break;
case "double":
$theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
break;
case "date":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "defined":
$theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
break;
}
return $theValue;
}
}
mysql_select_db($database_speedycms, $speedycms);
$query_caseStatus = "SELECT progress FROM tbl_accident WHERE id=$client_id";
$caseStatus = mysql_query($query_caseStatus, $speedycms) or die(mysql_error());
$row_caseStatus = mysql_fetch_assoc($caseStatus);
$totalRows_caseStatus = mysql_num_rows($caseStatus);
mysql_select_db($database_speedycms, $speedycms);
$query_retrieveSolicitor = "SELECT * FROM tbl_solicitors";
$retrieveSolicitor = mysql_query($query_retrieveSolicitor, $speedycms) or die(mysql_error());
$row_retrieveSolicitor = mysql_fetch_assoc($retrieveSolicitor);
$totalRows_retrieveSolicitor = mysql_num_rows($retrieveSolicitor);
mysql_select_db($database_speedycms, $speedycms);
$query_currentSolicitor = "SELECT currentSolicitor FROM tbl_accident WHERE id=$client_id";
$currentSolicitor = mysql_query($query_currentSolicitor, $speedycms) or die(mysql_error());
$row_currentSolicitor = mysql_fetch_assoc($currentSolicitor);
$totalRows_currentSolicitor = mysql_num_rows($currentSolicitor);
?>
答案 0 :(得分:1)
您的问题不是PHP_SELF
。您得到的错误是因为您创建的某个SQL语句不是有效的SQL,因此MySQL服务器会拒绝它。
查找每一行
mysql_query($query_someQuery, $speedycms)
在每行之前,添加类似
的语句echo $query_someQuery, "<br />","\n";
mysql_query($query_someQuery, $speedycms)
其中$query_someQuery
是您使用的实际变量。然后运行脚本/加载页面并检查SQL。它将有一个语法错误(如果浏览器看到实际返回的内容,请务必查看源代码)。
确定语法错误后,请跟踪代码并找出生成错误SQL的原因。
答案 1 :(得分:1)
如果你使用从外部取的client_id
,你应该将它括在单引号中,即使它被转义并且应该是一个整数:
SELECT progress FROM tbl_accident WHERE id='$client_id'
例如,如果脚本传递空client_id
,则此查询将变为:
SELECT progress FROM tbl_accident WHERE id=
,这是无效的SQL
并导致相同的错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
,您可以使用任何查询工具轻松复制。
答案 2 :(得分:0)
当你使用“php echo $ _SERVER ['PHP_SELF']”时,你确定问题是什么? 引发的错误是SQL语法错误,与调用php echo $ _SERVER ['PHP_SELF']无关。
错误说“在第1行”的事实是没用的,因为它意味着在SQL语法的第一行,而不是特定的页面,所以并没有真正指出你在哪里调用查询。
答案 3 :(得分:0)
尝试在此部分之后回显$ client_id:
$client_id = mysql_real_escape_string($_GET['id']);
您稍后在查询中使用它,如果它出现空白或无效,则可能会生成SQL错误。