如何使用Hibernate Criteria选择嵌套属性

时间:2013-11-06 09:01:07

标签: hibernate

我有三个实体,例如注册,用户和国家。基本上,注册属于用户,用户属于国家。现在我尝试从以下

注册中选择国家/地区名称
        Criteria criteria = getSession().createCriteria(Registration.class);
        ProjectionList projectionList = Projections.projectionList();
        criteria.createAlias("user.country", "usercountry");
        projectionList.add(Projections.property("usercountry.name"),"usercountry.name");
        criteria.setProjection(projectionList);
        criteria.list();

这失败并给我:

ERROR: org.hibernate.engine.jdbc.spi.SqlExceptionHelper - Unknown column 'usercountr1_.name' in 'field list'
org.hibernate.exception.SQLGrammarException: Unknown column 'usercountr1_.name' in 'field list'

生成的Hibernate查询:

Hibernate: select usercountr1_.name as y0_ from voucherList this_

我注意到sql中没有连接。这是查询失败的原因吗?我该如何解决这个问题?

1 个答案:

答案 0 :(得分:13)

尝试类似

的内容
Criteria criteria = getSession().createCriteria(Registration.class);
ProjectionList projectionList = Projections.projectionList();

criteria.createAlias("user", "u");  // here i changed 
criteria.createAlias("u.country", "usercountry");  //  here i have changed 

projectionList.add(Projections.property("usercountry.name"),"usercountry.name");
criteria.setProjection(projectionList);
criteria.list();