Question

我有一些代码，用户在EditText中输入数字。

根据输入内容的值，我想设置一个由对话框片段拉出的字符串（我现在用吐司取代，直到我可以修改字符串位。）

我得到了更改为int的pushups输入。该int在其下面的逻辑中与某些标准进行比较。根据它的位置，我希望它改变一个字符串，一旦完成所有逻辑，它将在稍后显示。

package com.mynavy;


import android.app.Activity;
import android.app.AlertDialog;
import android.app.Dialog;
import android.app.DialogFragment;
import android.content.DialogInterface;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

public class PRTC extends Activity {
    String pushs;
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.prtc);
        Button submit = (Button) findViewById(R.id.submit);



    submit.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            EditText age = (EditText) findViewById(R.id.agetxt);
            EditText pushups = (EditText) findViewById(R.id.pushups);
            EditText situps = (EditText) findViewById(R.id.situps);
            EditText runtime = (EditText) findViewById(R.id.runtime);
            String agetxt = String.valueOf(age.getText().toString());
            int agen = Integer.valueOf(agetxt);
            String pushtxt = String.valueOf(pushups.getText().toString());
            int pushn = Integer.valueOf(pushtxt);
            String sittxt = String.valueOf(situps.getText().toString());
            int sitn = Integer.valueOf(sittxt);
            String runtxt = String.valueOf(runtime.getText().toString());
            int runn = Integer.valueOf(runtxt);

//CHANGE THESE WHEN NEW INSTRUCTIONS COME OUT!!         
            if (agen >= 17 || agen <=20) {

                if (pushn >=20 || pushn <=30){
                    String pushs = "Good";
                }else if (pushn >=31 || pushn <=40){
                    String pushs = "Excellent";
                }else if (pushn >=41 || pushn <=50){
                    String pushs = "Outstanding";}}

                if (sitn >= 20 || sitn <= 30){
                    String sits = "Good";
                }else if (sitn >= 31 || sitn <=40){
                    String sits = "Excellent";
                }else if (sitn >= 41 || sitn <=50){
                    String sits = "Outstanding";

                    Toast.makeText(getBaseContext(), pushs + "Score.", Toast.LENGTH_SHORT).show();

            }else{
                Toast.makeText(getBaseContext(), "TEST FAILED!!", Toast.LENGTH_SHORT).show();
            }


        };});
}}

我知道我最近一直在问很多，但是所提供的任何帮助都将一如既往地受到极大的赞赏！

Answer 1

您的变量仅在声明它们的范围内是已知的。例如：

if(pushn >=20 || pushn <=30){
     String pushs = "Good";
}

如果这个pushs，

if将无法在范围之外被识别，您将收到编译错误：

pushs cannot be resolved to a variable

Answer 2

你正在重新声明你已经在onCreate之前声明的pushs，它是全局的，如果/ else块是本地的，其范围在{}内，则会向内推送。因此你需要删除 String 在推送之前使用if和else block.Also你的Toast也在最后一个if if block因此你没有得到Toast msg。像这样改变你的代码

           if (agen >= 17 || agen <=20) {

                if (pushn >=20 || pushn <=30){
                    pushs = "Good";
                }else if (pushn >=31 || pushn <=40){
                    pushs = "Excellent";
                }else if (pushn >=41 || pushn <=50){
                   pushs = "Outstanding";
                 }


                if (sitn >= 20 || sitn <= 30){
                   String sits = "Good";
                }else if (sitn >= 31 || sitn <=40){
                   String sits = "Excellent";
                }else if (sitn >= 41 || sitn <=50){
                   String sits = "Outstanding";
                }

            Toast.makeText(getBaseContext(), pushs + "Score.",Toast.LENGTH_SHORT).show();
            }
            else{
                Toast.makeText(getBaseContext(), "TEST FAILED!!", Toast.LENGTH_SHORT).show();
            }

在此之后一切都会正常工作

我试图从if语句获取字符串的值到主类

2 个答案: