仅获取节点

Question

我有一个包含许多文本字段和其他控件的锚点窗格。我想获取所有控件及其名称和id的值。

例如：如何清除所有文本字段值？

Answer 1

直截了当的解决方案是遍历AnchorPane的所有子项并寻找TextFields：

for (Node node : anchorPane.getChildren()) {
    System.out.println("Id: " + node.getId());
    if (node instanceof TextField) {
        // clear
        ((TextField)node).setText("");
    }
}

Answer 2

如果您需要递归方式测试，

public class NodeUtils {

    public static <T extends Pane> Map<Node, Object> formValues(T parent) {
        return formValues(parent, new HashMap<>());
    }

    private static <T extends Pane> Map<Node, Object> formValues(T parent, Map<Node, Object> map) {
        for (Node node : parent.getChildren()) {
            // Nodes - You can add more.
            if (node instanceof TextField) {
                map.put(node, ((TextField) node).getText());
            }
            if (node instanceof PasswordField) {
                map.put(node, ((PasswordField) node).getText());
            }
            if (node instanceof TextArea) {
                map.put(node, ((TextArea) node).getText());
            }
            if (node instanceof CheckBox) {
                map.put(node, ((CheckBox) node).isSelected());
            }

            // Recursive.
            if (node instanceof Pane) {
                formValues((Pane) node, map);
            }

        }

        return map;
    }
}

测试源，

Map<Node, Object> formValues = NodeUtils.formValues(source);

仅获取节点

public class NodeUtils {

    public static ArrayList<Node> getAllNodes(Parent root) {
        ArrayList<Node> nodes = new ArrayList<>();
        addAllDescendents(root, nodes);
        return nodes;
    }

    private static void addAllDescendents(Parent parent, ArrayList<Node> nodes) {
        // Get children.
        List<Node> children = Collections.EMPTY_LIST;
        if (parent instanceof ButtonBar) {
            children = ((ButtonBar) parent).getButtons();
        } else if (parent instanceof TabPane) {
            for (Tab tab : ((TabPane) parent).getTabs()) {
                Node tabContent = tab.getContent();
                if (tabContent instanceof Parent) {
                    addAllDescendents((Parent) tab.getContent(), nodes);
                } else {
                    // You can log and get a type that is not supported.
                }
            }
        } else {
            children = parent.getChildrenUnmodifiable();
        }

        // Add nodes.
        for (Node node : children) {
            nodes.add(node);
            if (node instanceof Parent) {
                addAllDescendents((Parent) node, nodes);
            }
        }
    }
}

测试源，

List<Node> nodes = NodeUtils.getAllNodes(aPaneOrAnotherParentObject);

Answer 3

这是一个Java 8版本：

if (AccessibilityManager.getInstance(context).isEnabled()) {
    AccessibilityEvent event = AccessibilityEvent.obtain(
                AccessibilityEvent.TYPE_ANNOUNCEMENT);
    onInitializeAccessibilityEvent(event);
    event.getText().add("some text");
    event.setContentDescription(null);
    yourContentView.requestSendAccessibilityEvent(this, event);
}

获取javafx中的所有文本字段值和ID

3 个答案:

仅获取节点