单击时没有运行的任何原因?我似乎无法弄明白。
<button id="button-container-like" onclick="rate($(this).attr(\'id\'))"><span class="thumbs-up"></span>Like</button>
<script>
function rate(rating){
var data = 'rating='+rating+'&id=<?php echo $eventId; ?>&userid56=<?PHP echo $userid55; ?>';
$.ajax({
type: 'POST',
url: 'includes/rate.php', //POSTS FORM TO THIS FILE
data: data,
success: function(e){
$(".ratings").html(e); //REPLACES THE TEXT OF view.php
}
});
}
</script>
答案 0 :(得分:1)
你去:
<button id="button-container-like" ><span class="thumbs-up"></span>Like</button>
<script>
jQuery(document).ready(function () {
$("#button-container-like").click(function() {
rate($(this).attr("id"));
});
function rate(rating) {
var data = 'rating=' + rating + '&id=<?php echo $eventId; ?>&userid56=<?PHP echo $userid55; ?>';
$.ajax({
type: 'POST',
url: 'includes/rate.php', //POSTS FORM TO THIS FILE
data: data,
success: function(e) {
$(".ratings").html(e); //REPLACES THE TEXT OF view.php
}
});
}
});
</script>
答案 1 :(得分:0)
如果此代码中没有其他内容,请从onclick
代码中删除斜杠。它们是不必要的并导致错误。
onclick="rate($(this).attr('id'))"