com.google.gson.internal.LinkedHashTreeMap无法强制转换为我的对象

时间:2013-11-05 18:55:33

标签: java json gson

我的JSON文件看起来像

{
    "SUBS_UID" : {
        "featureSetName" : "SIEMENSGSMTELEPHONY MULTISIM",
        "featureName" : "MULTISIMIMSI",
        "featureKey" : [{
                "key" : "SCKEY",
                "valueType" : 0,
                "value" : "0"
            }
        ]
    },
}

因此密钥是字符串“SUBS_ID”,值是名为FeatureDetails的模型,其中包含属性“featureSetName,featureName,...”。 所以我使用像这样的google.json lib从JSON文件中读取,

HashMap<String, FeatureDetails> featuresFromJson = new Gson().fromJson(JSONFeatureSet, HashMap.class);

然后我试图遍历这个HashMap获取值并将其转换为我的FeatureDetails模型,

for (Map.Entry entry : featuresFromJson.entrySet()) {
                    featureDetails = (FeatureDetails) entry.getValue();
                }

这是我的FeatureDetails模型,

public class FeatureDetails {

    private String featureSetName;
    private String featureName;
    private ArrayList<FeatureKey> featureKey;
    private String groupKey;
    private String groupValue;

    public FeatureDetails() {
        featureKey =  new ArrayList<FeatureKey>();
    }

    public ArrayList<FeatureKey> getFeatureKey() {
        return featureKey;
    }

    public void setFeatureKey(ArrayList<FeatureKey> featureKey) {
        this.featureKey = featureKey;
    }

    public String getGroupKey() {
        return groupKey;
    }

    public void setGroupKey(String groupKey) {
        this.groupKey = groupKey;
    }

    public String getGroupValue() {
        return groupValue;
    }

    public void setGroupValue(String groupValue) {
        this.groupValue = groupValue;
    }

    public String getFeatureName() {
        return featureName;
    }

    public void setFeatureName(String featureName) {
        this.featureName = featureName;
    }

    public String getFeatureSetName() {
        return featureSetName;
    }

    public void setFeatureSetName(String featureSetName) {
        this.featureSetName = featureSetName;
    }
} 

但我得到一个例外“com.google.gson.internal.LinkedHashTreeMap无法转换为com.asset.vsv.models.FeatureDetail”。

4 个答案:

答案 0 :(得分:32)

试试这个:

HashMap<String, FeatureDetails> featuresFromJson = new Gson().fromJson(JSONFeatureSet, new TypeToken<Map<String, FeatureDetails>>() {}.getType());

当你浏览哈希映射时,请执行以下操作:

for (Map.Entry<String, FeatureDetails> entry : featuresFromJson.entrySet()) {
                    FeatureDetails featureDetails = entry.getValue();
}

答案 1 :(得分:5)

您之所以看到这一点,是因为您要告诉GSON使用行中HashMap的结构反序列化JSON结构

... = new Gson().fromJson(JSONFeatureSet, HashMap.class);
                                          ^^
                                          Right here

因此,即使结构可能与FeatureDetails对象的结构匹配,GSON也不知道JSON中的子对象是除简单键值对之外的其他对象。

一种解决方案是创建一个包装FeatureDetails对象的模型,该对象将充当整个结构的根。此对象可能如下所示:

public class FeatureDetailsRoot{
    private FeatureDetails SUBS_UID; // poor naming, but must match the key in your JSON
}

最后,你通过那个模特的课程:

= new Gson().fromJson(JSONFeatureSet, FeatureDetailsRoot.class)

<强>更新

在关于添加/拥有多个FeatureDetails对象的能力的评论中回答您的问题时,目前的问题是您的JSON不反映这种结构。意思是,"SUBS_UID"键指向单个对象,而不是数组对象。如果你想拥有这种能力,那么你的json需要被改变,以便它显示一个对象数组,如下所示:

{
    "SUBS_UID" : [{
       "featureSetName" : "Feature set name #1",
       ...attributes for feature #1
     },
     {
       "featureSetName" : "Feature set name #2",
       ...attributes for feature #2
     },
     ...other features
     ]
}

然后您可以简单地更改根类,使其包含FeatureDetails个对象的列表,如下所示:

public class FeatureDetailsRoot{
    private List<FeatureDetails> SUBS_UID;
}

让我知道这是否有意义(或者我是否误解了你)

答案 2 :(得分:0)

代码在Kotlin中: 使用val type = object : TypeToken<HashMap<String, FoodLogEntry>>() {}.type Gson().fromJson(dataStr, type)

而不是val type = object : TypeToken<Map<String, FoodLogEntry>>() {}.type Gson().fromJson(dataStr, type) 注意:HashMap而不是Map

答案 3 :(得分:0)

(objectName as Map<String, Any>).get("fieldName")