Question

到目前为止，我写了这篇文章：

SELECT 
    Query,
    SUM(CASE WHEN SearchDate >= '2012-01-01' and SearchDate < '2013-01-01' THEN 1 ELSE 0 END) as Year2012,
    SUM(CASE WHEN SearchDate >= '2013-01-01' and SearchDate < '2014-01-01' THEN 1 ELSE 0 END) as Year2013
FROM dbo.tblSearch WITH (NOLOCK)
WHERE DomainProjectID=13
GROUP BY Query

它查看表格中的查询（搜索）术语，并计算每个在给定日期范围内出现的次数（在本例中为今年和最后一次）。

在结果中，我想只显示那些出现100次或更多次的内容。现在它显示了所有。

Query     Year2012   Year2013
beavers   90         87
hair      4          14

如果最好的方法不涉及CASE WHEN，请告诉我！初学者。

Answer 1

使用其他having子句

SELECT 
    Query,
    SUM(CASE WHEN SearchDate >= '2012-01-01' and SearchDate < '2013-01-01' THEN 1 ELSE 0 END) as Year2012,
    SUM(CASE WHEN SearchDate >= '2013-01-01' and SearchDate < '2014-01-01' THEN 1 ELSE 0 END) as Year2013
FROM dbo.tblSearch WITH (NOLOCK)
WHERE DomainProjectID=13
GROUP BY Query
having 
  SUM(CASE WHEN SearchDate >= '2012-01-01' and SearchDate < '2014-01-01' 
           THEN 1 
           ELSE 0 
      END) >= 100

Answer 2

我认为这更清晰，更容易维护：

SELECT 
    Query,
    SUM(CASE WHEN year(SearchDate) = 2012 THEN 1 ELSE 0 END) as Year2012,
    SUM(CASE WHEN year(SearchDate) = 2013 THEN 1 ELSE 0 END) as Year2013
FROM dbo.tblSearch WITH (NOLOCK)
WHERE DomainProjectID=13
GROUP BY Query
having 
   SUM(CASE WHEN year(SearchDate) in (2012, 2013) THEN 1 ELSE 0 END)  
  >= 100

SQL - 仅在count高于xx时显示结果

2 个答案: