我正在打印前10个数字的阶乘,所以它是0 - 9.以下代码适用于我。但我无法使循环使得0的阶乘也在循环内。任何建议表示赞赏。谢谢。
public class fact {
public static void main(String[] args) {
System.out.println("\n\n(f) Loop to print first 10 factorial numbers");
System.out.println("\nFactorial of 0 is 1");
int fact = 1;
int index = 1;
while (index < 10)
{
fact*=index;
System.out.println("Factorial of " + index + " is " + fact);
index++;
}
}
}
答案 0 :(得分:1)
如何在if
循环中为索引0添加while
条件
int fact = 1;
int index = 0;
while (index < 10)
{
if(index == 0)
System.out.println("\nFactorial of 0 is 1");
else {
fact*=index;
System.out.println("Factorial of " + index + " is " + fact);
}
index++;
}
答案 1 :(得分:1)
因子0是一种特殊情况,因此最好在循环外打印它,就像现在一样。
答案 2 :(得分:1)
对于大n个数字,找到阶乘及其数字计数。
import java.util.Scanner;
public class N_Faktorial {
public static void main(String [] args)
{
int u=1,A[]=new int[9999999];
Scanner scan =new Scanner(System.in);
System.out.print("n=");
int n=scan.nextInt();
A[1]=1;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++) {
A[j]*=i;
}
for(int j=1;j<=n;j++)
{
if(A[j]>9)
{
A[j+1]+=A[j]/10;
A[j]%=10;
}
if(A[u+1]!=0) {
u++;
}
}
}
System.out.print(n+"! digit count:"+u+"\\n Result: \\n");
for(int i=u;i>=1;i--)
{
System.out.print(A[i]);
}
}
}
答案 3 :(得分:0)
你可以这样做
int fact = 1;
int index = 0;
while (index < 10)
{
fact=(index==0)?1:fact*(index);
System.out.println("Factorial of " + index + " is " + fact);
index++;
}
答案 4 :(得分:0)
factorialList(10);
public static int factorialList(int indexMax) {
int fact = 1;
if (indexMax > 0) fact = indexMax * factorialList(indexMax - 1);
System.out.println("Factorial of " + indexMax + " is " + fact);
return fact;
}
Fn调用不如循环有效,但我敢打赌它会优化到相同的大小任务。