Question

我可以提交表单，将数据推送到数据库，然后以我的servlet成功/错误消息结束。但是我仍然需要将重定向回html格式以及相关结果：

1）成功叠加（要触发的现有javascript方法）和所有表单字段为空

2）错误消息（表单字段仍包含输入值）

这些是我目前拥有（提取）的代码和文件：

Form.java

protected void contructAndSendResponse(HttpServletResponse response, String responseStatus, String... responseErrorCodes) throws Exception {
    StringBuilder responseMsg = new StringBuilder();
    responseMsg.append(Form.RESPONSE_DATA_STATUS);
    responseMsg.append(responseStatus);
    if (responseErrorCodes == null || responseErrorCodes.length == 0) {
        responseMsg.append(Form.JSON_CLOSE_OBJECT);
    }
    else {
        responseMsg.append(Form.RESPONSE_DATA_ERROR_CODE);
        responseMsg.append(Form.JSON_BEGIN_ARRAY);
        int errorCodeLength = responseErrorCodes.length;
        for (int i = 0; i < errorCodeLength; i++) {
            responseMsg.append(Form.JSON_DOUBLE_QUOTE);
            responseMsg.append(responseErrorCodes[i]);
            responseMsg.append(Form.JSON_DOUBLE_QUOTE);
            if (i < errorCodeLength - 1) {
                responseMsg.append(Form.JSON_COMMA);
            }
        }
        responseMsg.append(Form.JSON_END_ARRAY);
        responseMsg.append(Form.JSON_CLOSE_OBJECT);
    }
    contructAndSendResponse(response, responseMsg.toString());
}

protected void contructAndSendResponse(HttpServletResponse response, String responseMsg) throws Exception {
    ServletOutputStream outStream = response.getOutputStream();
    response.setContentType(Util.CONTENT_TYPE_JSON);
    outStream.print(responseMsg);
    outStream.flush();
    outStream.close();
}

public void returnResponse(HttpServletResponse response, String responseStatus, String... responseErrorCodes) {
    try {
        contructAndSendResponse(response, responseStatus, responseErrorCodes);
    }
    catch (Exception e) {
    }
}

Servlet.java

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    processRequest(request, response);
}

private void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    Form onlineForm = null;
    List<String> errorCodes = new ArrayList<String>();
    try {
        onlineForm = FormFactory.getInstance().createObject(formtype);
        onlineForm.extractRequest(request);
        errorCodes = onlineForm.validateInputParam();
        if (errorCodes == null || errorCodes.isEmpty()) {
            Connection conn = PersistentFactory.getInstance().openConnection();
            responseStatus = Form.RESPONSE_DATA_STATUS_SUCCESS;
            PersistentFactory.getInstance().closeConnection(conn);
        }
    }
    catch (Exception e) {
        errorCodes.add(EntityUtils.ErrorCode.E1.name());
    }
    onlineForm.returnResponse(response, responseStatus, errorCodes.toArray(new String[0]));
}

Form.jsp

<form id="form" action="/projectx/form?type=contact" class="custom-ui" method="POST" >
    ....
</form>
<script type="text/javascript">
function overlay(){
        Projectx.modalDialog({
            elem: "#form",
            title: "Success",
            body: "Thank you",
            tpl: "modal-tpl"
        });
    }
</script>

我已尝试过这些但重定向不适用于我的上述代码：

- dispatcher.forward(request,response);
- forward(responsePage, aRequest, aResponse);
- redirect(responsePage, response);

Answer 1

我找到了一个简单的解决方案。由于我的服务器端返回了json响应，我将客户端（js）脚本更改为：

$("#form").click(function(){
   $.ajax({
       url: '/projectx/servlet',
       type: 'POST',
       data: $('#form').serialize(),
       success:function(data){
          if(data.status=="success"){
               success();
               $("#form").trigger("reset");
          }else{
               checkagain();
          }
       },
       error:function(data){
           error();
       }
    });
});

如何在JSP表单提交后重定向回html（带有成功/错误消息）

1 个答案: