Question

我想从我传递给类的目录中获取所有文件大小，并且我希望它们按其扩展名进行排序，例如：

.exe:  
file1.exe ....... 254KB
file1.exe ....... 544KB
file1.exe ....... 254KB

如果他们有任何其他扩展希望他们像这样写

下面是我到目前为止编写的代码，但我不知道如何对数据进行排序：

public FileTools(string directoryPath,string searchPattern)
{
    DirectoryPath = directoryPath;
    SearchPattern = searchPattern;
    TotallFiles = new List<FileInfo>();
    CalculateFiles();
}
private void CalculateFiles()
{
  foreach (var item in new DirectoryInfo(this.DirectoryPath).GetFiles(SearchPattern,SearchOption.AllDirectories))
     {

     }
 }

我希望在FileInfo中填充List个对象，然后按照示例对它们进行排序和编写。

Answer 1

按扩展名对文件进行分组，然后对这些组进行排序。然后，您可以通过循环每个扩展来获得输出。请参阅此示例：

private void CalculateFiles()
{
    var builder = new StringBuilder();
    var fileGroupByExtension = new DirectoryInfo(this.DirectoryPath)
                                    .GetFiles(SearchPattern,SearchOption.AllDirectories)
                                    .GroupBy(file => file.Extension)
                                    .OrderBy(grp => grp.Key);
    foreach (var grp in fileGroupByExtension)
    {
        var extension = grp.Key;
        builder.Append(extension);
        builder.Append(":");
        builder.AppendLine();
        foreach (var file in grp.OrderBy(file => file.Name))
        {
            builder.Append(file.Name);
            builder.Append(" ....... ");
            builder.Append(file.Length / 1000);
            builder.Append("KB");
            builder.AppendLine();
        }
    }
    Console.Write(builder.ToString());
}

Answer 2

试试这个;

    var sortedList = Directory.EnumerateFiles(
        directoryPath, 
        searchPattern, 
        SearchOption.AllDirectories)
        .OrderBy(item => Path.GetExtension(item));

请记住加入using System.Linq;

Answer 3

这应该可以使用LINQ：

var files = new DirectoryInfo(this.DirectoryPath).GetFiles(SearchPattern,SearchOption.AllDirectories);
var ordered_files = from f in files
                    orderby f.Extension
                    select f;

获取文件信息

3 个答案: