Question

import random

def main():
    uinput()

def uinput():
    times = int(input('How many numbers do you want generated?'))
    number1 = int(input('Put in the first number:' ))
    number2 = int(input('Put in the second number:'))
    rnumber = random.randint(number1, number2)
    print (rnumber)



main()

我在Python中乱搞，我希望我的程序生成随机数。如你所见，我已经完成了这个。接下来我要做的是让它生成多个随机数，具体取决于“用户”想要生成的数量。我该怎么做呢？我假设需要一个循环。

Answer 1

使用“for”循环。例如：

for i in xrange(times):
    # generate random number and print it

Answer 2

这将生成范围number1到number2

的随机整数列表

rnumber = [random.randint(number1, number2) for x in range(times)]

有关详细信息，请查看List Comprehension.

Answer 3

使用生成器和迭代器：

import random
from itertools import islice

def genRandom(a, b): 
    while True:
        yield random.randint(a, b)


number1 = int(input('Put in the first number:' ))
number2 = int(input('Put in the second number:'))
total = int(input('Put in how many numbers generated:'))

rnumberIterator = islice(genRandom(number1, number2), total)

Answer 4

我建议使用一个简单地添加到现有字符串的循环：

import random
from random import randint
list=""
number1=input("Put in the first number: ")
number2=input("Put in the second number: ")
total=input("Put in how many numbers generated: ")
times_run=0
while times_run<=total:
    gen1=random.randint(number1, number2)
    list=str(list)+str(gen1)+" "
    times_run+=1
print list

Answer 5

此代码选择一个随机数：

import random
x = (random.randint(1, 50))
print ("The number is ", x)

重复代码6次，选择6个随机数。

Python随机数多次

5 个答案: