以下是我的要求。我们可以使用XSLT做到这一点吗?我想将AttributeName的值转换为策略下的标记,并将相应的AttributeValue转换为值。
输入:
<Policy>
<Attributes>
<AttributeName>is_policy_loan</AttributeName>
<AttributeValue>Yes</AttributeValue>
</Attributes>
<Attributes>
<AttributeName>is_policy_owners</AttributeName>
<AttributeValue>Yes</AttributeValue>
</Attributes>
<Attributes>
<AttributeName>is_policy_twoyears</AttributeName>
<AttributeValue>Yes</AttributeValue>
</Attributes>
</Policy>
输出:
<Policy>
<is_policy_loan>Yes</is_policy_loan>
<is_policy_owners>Yes</is_policy_owners>
<is_policy_twoyears>Yes</is_policy_twoyears>
</Policy>
答案 0 :(得分:1)
以下xsl
文件将完成此任务:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- create the <AttributeName>AttributeValue</..> nodes -->
<xsl:template match="//Attributes">
<xsl:variable name="name" select="AttributeName" />
<xsl:element name="{$name}">
<xsl:value-of select="AttributeValue" />
</xsl:element>
</xsl:template>
<!-- wrap nodes in a `Policy` node -->
<xsl:template match="/">
<Policy>
<xsl:apply-templates/>
</Policy>
</xsl:template>
</xsl:stylesheet>
答案 1 :(得分:1)
我会这样做,
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="xml" indent="yes" encoding="UTF-8" omit-xml-declaration="yes" />
<xsl:template match="Policy">
<xsl:element name="Policy">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
<xsl:template match="Attributes">
<xsl:variable name="name" select="AttributeName" />
<xsl:element name="{$name}">
<xsl:value-of select="AttributeValue" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
输出将是,
<Policy>
<is_policy_loan>Yes</is_policy_loan>
<is_policy_owners>Yes</is_policy_owners>
<is_policy_twoyears>Yes</is_policy_twoyears>
</Policy>