在网站上找不到任何其他答案。如果运行了else并显示错误消息,是否可以通过循环回到开始而不是重新启动控制台来重新启动程序?
class Program
{
static void Main(string[] args)
{
int User;
int Array;
StreamWriter outfile = new StreamWriter("C://log.txt");
Console.WriteLine("Input an number between 1 and 100");
User = Convert.ToInt32(Console.ReadLine());
if (User < 101 && User > 0)
{
for (Array = 1; Array <= User; Array++)
{
Console.WriteLine(Array + ", " + Array * 10 * Array);
outfile.WriteLine(Array + ", " + Array * 10 * Array);
}
{
Console.WriteLine("Press Enter To Exit The Console");
outfile.Close();
Console.ReadLine();
}
}
else
{
Console.WriteLine("Sorry you input an invalid number. ");
Console.ReadLine();
}
}
}
抱歉!为了更清楚,如果用户输入无效数字
,我需要再次启动程序感谢您的帮助!
答案 0 :(得分:4)
你可以这样做
User = Convert.ToInt32(Console.ReadLine());
while (User >= 101 || User <= 0)
{
Console.WriteLine("Sorry you input an invalid number. ");
User = Convert.ToInt32(Console.ReadLine());
}
答案 1 :(得分:3)
一种简单的方法是将代码置于while循环中,以便代码不断重复。 退出循环的唯一方法是将您在if
子句中设置的条件设置为true。所以有些东西:
class Program
{
static void Main(string[] args)
{
int User;
int Array;
bool isUserWrong = true; //This is a flag that we will use to control the flow of the loop
StreamWriter outfile = new StreamWriter("C://log.txt");
while(isUserWrong)
{
Console.WriteLine("Input an number between 1 and 100");
User = Convert.ToInt32(Console.ReadLine());
if (User < 101 && User > 0)
{
for (Array = 1; Array <= User; Array++)
{
Console.WriteLine(Array + ", " + Array * 10 * Array);
outfile.WriteLine(Array + ", " + Array * 10 * Array);
}
isUserWrong = false; // We signal that we may now leave the loop
}
else
{
Console.WriteLine("Sorry you input an invalid number. ");
Console.ReadLine();
//Note that here we keep the value of the flag 'true' so the loop continues
}
}
Console.WriteLine("Press Enter To Exit The Console");
outfile.Close();
Console.ReadLine();
}
}
答案 2 :(得分:0)
这对Java中的do-while循环很有用:
class DoWhileDemo {
public static void main(String[] args){
int count = 1;
do {
System.out.println("Count is: " + count);
count++;
} while (count < 11);
}
}