Question

while answer  == 'Y':
    roll = get_a_roll()
    display_die(roll)
    if roll == first_roll:
        print("You lost!")
    amount_won = roll
    current_amount = amount_earned_this_roll + amount_won
    amount_earned_this_rol = current_amoun
    print("You won $",amount_won)
    print(  "You have $",current_amount)
    print("")
    answer = input("Do you want to go again? (y/n) ").upper()


if answer == 'N':
    print("You left with $",current_amount)
else:
    print("You left with $",current_amount)

使用此循环的目的是在游戏中，掷骰子，并且每个卷的数量奖励你，除非你滚动匹配你的第一卷。现在，我需要循环停止，如果发生这种情况，我知道这很容易使用break语句实现，但是，我已经被告知不允许使用break语句。如果roll == first_roll？

，如何让循环终止？

Answer 1

你可以：

使用标志变量;你已经在使用它了，只需在这里重复使用它：

running = True
while running:
    # ...
    if roll == first_roll:
        running = False
    else:
        # ...
        if answer.lower() in ('n', 'no'):
            running = False
        # ...

从函数返回：

def game():
    while True:
        # ...
        if roll == first_roll:
            return
        # ...
        if answer.lower() in ('n', 'no'):
            return
        # ...

提出异常：

class GameExit(Exception):
    pass

try:
    while True:
        # ...
        if roll == first_roll:
            raise GameExit()
        # ...
        if answer.lower() in ('n', 'no'):
            raise GameExit()
        # ...
except GameExit:
    # exited the loop
    pass

Answer 2

如果要退出循环，可以使用要设置为false的变量。

cont = True
while cont:
    roll = ...
    if roll == first_roll:
        cont = False
    else:
        answer = input(...)
        cont = (answer == 'Y')

Answer 3

获得一些奖励积分和注意力，使用生成器功能。

from random import randint

def get_a_roll():
    return randint(1, 13)

def roll_generator(previous_roll, current_roll):
    if previous_roll == current_roll:
        yield False
    yield True

previous_roll = None 
current_roll = get_a_roll()

while next(roll_generator(previous_roll, current_roll)):
    previous_roll = current_roll
    current_roll = get_a_roll()
    print('Previous roll: ' + str(previous_roll))
    print('Current roll: ' + str(current_roll))
print('Finished')

Answer 4

是否允许continue？它可能与break太相似（两者都是受控goto的类型，其中continue返回到循环的顶部而不是退出它），但这是一种使用它的方法：

while answer  == 'Y':
    roll = get_a_roll()
    display_die(roll)
    if roll == first_roll:
        print("You lost!")
        answer = 'N'
        continue
    ...

如果丢失，answer被硬编码为“N”，因此当您返回顶部重新评估条件时，它将为false并且循环终止。

Answer 5

npm install -g @angular/cli

Answer 6

说明：你定义了一个 end_game 函数，它在最后做你想做的事情，然后结束代码

#do this 
def end_game()
    if answer == 'N':
        print("You left with $",current_amount)
    else:
        print("You left with $",current_amount)
        exit()
while answer  == 'Y':
    roll = get_a_roll()
    display_die(roll)
    if roll == first_roll:
        print("You lost!")
        end_game()
    amount_won = roll
    current_amount = amount_earned_this_roll + amount_won
    amount_earned_this_rol = current_amoun
    print("You won $",amount_won)
    print(  "You have $",current_amount)
    print("")
    answer = input("Do you want to go again? (y/n) ").upper()

在不使用break的情况下突破python循环

6 个答案: