我有一个NSDictionary看起来像这样:
data = {
start = {
name = "abc";
age = "123";
id = AA838DDE;
};
};
如何解析字典以获取个人姓名,年龄和身份证?感谢。
答案 0 :(得分:2)
NSString *name = dictionary[@"data"][@"start"][@"name"];
答案 1 :(得分:0)
我添加了另一个答案,因为我讨厌新的Objective-C语法(对不起@Raphael Olivieira)
NSString *name = [[[[dictionary objectForKey:@"data"] objectForKey:@"start"] objectAtIndex:0] objectForKey:@"name"];
NSLog(@"%@", name);
比上一个答案更长,但你知道你做了什么,而且你不用C编码。
BTW,使用其他语法:
NSString *name = dictionary[@"data"][@"start"][0][@"name"];
NSLog(@"%@", name);
答案 2 :(得分:0)
为什么不试试:
int arrCount = [[[dictionaryObject valueForKey:@"data"] objectForKey:@"start"] count];
for(int i = 0 ; i < arrCount ; i++)
{
NSString *strName = [[[[dictionaryObject objectForKey:@"data"]
objectForKey:@"start"]
objectAtIndex:i]
objectForKey:@"name"];
NSString *strAge = [[[[dictionaryObject objectForKey:@"data"]
objectForKey:@"start"]
objectAtIndex:i]
objectForKey:@"age"];
NSString *strID = [[[[dictionaryObject objectForKey:@"data"]
objectForKey:@"start"]
objectAtIndex:i]
objectForKey:@"id"];
NSLog(@"%@ - %@ - %@", strName, strAge, strID);
}