如何取出.gif,.jpg或.png

时间:2009-12-29 21:36:47

标签: php codeigniter upload

我使用Windows并显示文件扩展名。

当我使用PHP上传图像文件时,image1_big.jpg的图像名称变为image1_big.jpg.jpg。

image2.gif成为image2.gif.gif。

我不想关闭文件扩展名。

我该如何避免这个问题?

function addProduct(){
    $data = array( 
        'name' => db_clean($_POST['name']),
        'shortdesc' => db_clean($_POST['shortdesc']),
        'longdesc' => db_clean($_POST['longdesc'],5000),
        'status' => db_clean($_POST['status'],8),
        'class' => db_clean($_POST['class'],30),
        'grouping' => db_clean($_POST['grouping'],16),
        'category_id' => id_clean($_POST['category_id']),
        'featured' => db_clean($_POST['featured'],5),
        'price' => db_clean($_POST['price'],16)

    );

    if ($_FILES){
        $config['upload_path'] = './images/';
        $config['allowed_types'] = 'gif|jpg|png';
        $config['max_size'] = '200';
        $config['remove_spaces'] = true;
        $config['overwrite'] = false;
        $config['max_width']  = '0';
        $config['max_height']  = '0';
        $this->load->library('upload', $config);    
        if (strlen($_FILES['image']['name'])){
            if(!$this->upload->do_upload('image')){
                $this->upload->display_errors();
                exit();
            }
            $image = $this->upload->data();
            if ($image['file_name']){
                $data['image'] = "images/".$image['file_name'];
            }
        }
        if (strlen($_FILES['thumbnail']['name'])){
            if(!$this->upload->do_upload('thumbnail')){
                $this->upload->display_errors();
                exit();
            }
            $thumb = $this->upload->data();
            if ($thumb['file_name']){
                $data['thumbnail'] = "images/".$thumb['file_name'];
            }
        }
    }
    $this->db->insert('omc_products', $data);   

    $new_product_id = $this->db->insert_id();
...
...

2 个答案:

答案 0 :(得分:1)

如果您认为需要,可以删除文件扩展名。但是,我会赞同BalusC的评论,认为这不是PHP的正确行为:

$filename = substr($filename_passed_to_upload, 0, (strlen($filename_passed_to_upload) - 4));

或更严格地说:

$temp = explode(".", $filename_passed_to_upload);
$new_filename = $temp[0]; 
// be careful, this fails when the name has a '.' in it other than for the extention
// you'll probably want to do something with a loop with $temp

答案 1 :(得分:0)

basename函数将处理不必要的扩展,如果你告诉它如何:

$filename = dirname($old_filename) . '/' . basename($old_file_name, '.gif');

或者,有Perl正则表达式删除双扩展(这将处理所有双扩展和三扩展文件),因此只使用最后一个扩展。

#                                +-+-- handles .c through .jpeg
#                                | |
$filename = preg_replace('/(\\..{1,4}){2,}$/', '$1', $old_filename);
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