我正在试图弄清楚JSON现在是如何工作的,所以我想到了比制作一个小JSON阅读项目更好的方法!我希望用户使用EditText和Search按钮供用户使用,并查看用户输入的网站是否有任何JSON,然后将其显示在文本框中。现在我正在测试该网站: itunes.apple.com/search?term =
正如你在我的代码中看到的那样,我只是在没有EditText和Search按钮的情况下设置这些变量,直到我可以使这个东西工作。我收到以下错误:
11-03 20:30:58.545: E/AndroidRuntime(8608): FATAL EXCEPTION: AsyncTask #1
11-03 20:30:58.545: E/AndroidRuntime(8608): java.lang.RuntimeException: An error occured while executing doInBackground()
11-03 20:30:58.545: E/AndroidRuntime(8608): at android.os.AsyncTask$3.done(AsyncTask.java:299)
11-03 20:30:58.545: E/AndroidRuntime(8608): at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273)
11-03 20:30:58.545: E/AndroidRuntime(8608): at java.util.concurrent.FutureTask.setException(FutureTask.java:124)
11-03 20:30:58.545: E/AndroidRuntime(8608): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307)
11-03 20:30:58.545: E/AndroidRuntime(8608): at java.util.concurrent.FutureTask.run(FutureTask.java:137)
11-03 20:30:58.545: E/AndroidRuntime(8608): at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
11-03 20:30:58.545: E/AndroidRuntime(8608): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
11-03 20:30:58.545: E/AndroidRuntime(8608): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
11-03 20:30:58.545: E/AndroidRuntime(8608): at java.lang.Thread.run(Thread.java:856)
11-03 20:30:58.545: E/AndroidRuntime(8608): Caused by: java.lang.IllegalStateException:
Target host must not be null, or set in parameters. scheme=null, host=null, path=itunes.apple.com/search
我认为这是因为以下行: HttpResponse r = client.execute(get); 但我不知道如何将主机更正为null。我觉得它与问号或其他东西有关。或许我只是以错误的方式接近这个。请考虑这是我的第一个使用JSON的项目。也许我需要一个关于使用JSON的简单教程,以便我彻底理解它。谢谢!
MainActivity.java
public class MainActivity extends Activity implements OnClickListener {
TextView fetchText;
EditText httpEntryBox,jsonEntryBox;
Button search_button_http, search_button_json;
HTTP_Fetcher http_fetch;
HttpClient client;
final static String URL = "itunes.apple.com/search?term=";
JSONObject json;
InputMethodManager imm;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
fetchText = (TextView) findViewById(R.id.fetchText);
client = new DefaultHttpClient();
new Read().execute("artistName");
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
public JSONObject search( String searchItem ) throws ClientProtocolException, IOException, JSONException, URISyntaxException{
StringBuilder url = new StringBuilder(URL);
url.append(searchItem);
String finished_url = url.toString();
HttpGet get = new HttpGet(finished_url);
HttpResponse r = client.execute(get);
int status = r.getStatusLine().getStatusCode();
if (status == 200){
HttpEntity e = r.getEntity();
String data = EntityUtils.toString(e);
JSONArray array = new JSONArray(data);
return array.getJSONObject(0);
}else{
Log.e("Search","fetch error");
return null;
}
}
public class Read extends AsyncTask<String, Integer, String>{
@Override
protected String doInBackground(String... params) {
try {
json = search("lilwayne");
return json.getString(params[0]);
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
fetchText.setText(result);
}
}
}
答案 0 :(得分:3)
我认为你错过了 http 计划,所以不是:
final static String URL = "itunes.apple.com/search?term=";
放:
final static String URL = "http://itunes.apple.com/search?term=";
修改强>
即使这样可行,解析JSON也会失败,因为这一行:JSONArray array = new JSONArray(data);
- 这假定响应是一个数组,但它是一个包含两个条目的JSONObject:resultsCount
和results
。您需要将其设为JSONObject
:JSONObject obj = new JSONObject(data);
。互联网上充满了android json parsing
教程。这是一个relevant article。