Question

我无法弄清楚为什么我在下面收到此错误我已经包含了所有适当的jar（据我所知，我已经包含了eclipses .classpath文件。）所有的classpath条目都解决得很好。我错过了什么？

无法解析javax.servlet.ServletContextListener类型。它是从“extends GuiceServletContextListener”行中的必需.class文件间接引用的

-

import com.google.inject.Guice;
import com.google.inject.Injector;
import com.google.inject.servlet.GuiceServletContextListener;
import com.google.inject.servlet.ServletModule;


public class ServletConfig extends GuiceServletContextListener {

    @Override
    protected Injector getInjector() {
        return Guice.createInjector(new ServletModule(){
            @Override
            protected void configureServlets() {
                // TODO: add necessary code to bind 
           }

       });
    }

}

.Classpath

    <?xml version="1.0" encoding="UTF-8"?>
<classpath>
    <classpathentry kind="src" path="src"/>
    <classpathentry kind="con" path="org.eclipse.jdt.launching.JRE_CONTAINER/org.eclipse.jdt.internal.debug.ui.launcher.StandardVMType/jdk1.7.0_21">
        <attributes>
            <attribute name="owner.project.facets" value="java"/>
        </attributes>
    </classpathentry>
    <classpathentry kind="con" path="oracle.eclipse.tools.glassfish.lib.system">
        <attributes>
            <attribute name="owner.project.facets" value="jst.web"/>
        </attributes>
    </classpathentry>
    <classpathentry kind="con" path="org.eclipse.jst.j2ee.internal.web.container"/>
    <classpathentry kind="con" path="org.eclipse.jst.j2ee.internal.module.container"/>
    <classpathentry kind="lib" path="guice-3.0/aopalliance.jar"/>
    <classpathentry kind="lib" path="guice-3.0/guice-3.0.jar"/>
    <classpathentry kind="lib" path="guice-3.0/guice-servlet-3.0.jar"/>
    <classpathentry kind="lib" path="guice-3.0/javax.inject.jar"/>
    <classpathentry kind="output" path="build/classes"/>
</classpath>

Answer 1

Eclipse需要连接到glassfish服务器才能使其正常工作。

当SO让我时，会将此标记为正确。

构建路径问题学习Guice

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