在ASP MVC Api上我有树命名函数来检索数据,但我想将它们组合到一个请求StylesAll:{},这里是代码。
[ActionName("Styles")]
public IEnumerable<StyleDTO> GetStyles()
{
return from s in db.styles
select new StyleDTO() { Name = s.Name, StyleId = s.StyleId };
}
[ActionName("Labels")]
public IEnumerable<LabelDTO> GetLabels()
{
return from l in db.Labels
select new LabelDTO() { Name = l.Name, LabelId = l.LabelId , image = l.image};
}
[ActionName("Commodity")]
public IEnumerable<CommodityDTO> GetCommodity()
{
return from c in db.Commodities
select new CommodityDTO() { CommodityId = c.CommodityId, CreateDate = c.CreateDate, Name = c.Name, Varieties = ( from v in c.Varieties select new VarietyDTO()
{
CommodityId = v.CommodityId, Name = v.Name, VarietyId = v.VarietyId
}) };
}
答案 0 :(得分:3)
创建一个ViewModel以包含所有数据,然后创建函数以填充ViewModel并将其返回。
查看模型
public class AllStyles
{
public IEnumerable<StyleDTO> Commodities {get;set;}
public IEnumerable<LabelDTO> Labels {get;set;}
public IEnumerable<CommodityDTO> Styles {get;set;}
}
API操作方法
[ActionName("StylesAll")]
public AllStyles GetAllStyles()
{
return new AllStyles{
Styles = from s in db.styles
select new StyleDTO() {
Name = s.Name,
StyleId = s.StyleId },
Labels = from l in db.Labels
select new LabelDTO() {
Name = l.Name,
LabelId = l.LabelId ,
image = l.image},
Commodities = from c in db.Commodities
select new CommodityDTO() {
CommodityId = c.CommodityId,
CreateDate = c.CreateDate,
Name = c.Name,
Varieties = ( from v in c.Varieties
select new VarietyDTO() {
CommodityId = v.CommodityId,
Name = v.Name,
VarietyId = v.VarietyId})}
};
}