Question

我尝试使用以下代码在Python 3.2.3中保持与urllib.request的HTTP连接：

handler = urllib.request.HTTPHandler()
opener = urllib.request.build_opener(handler)
opener.addheaders = [("connection", "keep-alive"), ("Cookie", cookie_value)]
r = opener.open(url)

但是如果我听到与Wireshark的连接，我会得到一个标题为“Connection：closed”但是设置了Cookie。

Host: url
Cookie: cookie-value
Connection: close

如何将Headerinfo设置为Connection：keep-alive？

Answer 1

使用http-client

保持连接活跃

import http.client
conn = http.client.HTTPConnection(host, port)
conn.request(method, url, body, headers)

标题只是给dict而且正文仍然可以使用urllib.parse.urlencode。所以，你可以通过http客户端制作Cookie标题。

参考：
official reference

Answer 2

如果你需要比普通的http.client更自动的东西，这可能会有所帮助，虽然它不是线程安全的。

from http.client import HTTPConnection, HTTPSConnection
import select
connections = {}


def request(method, url, body=None, headers={}, **kwargs):
    scheme, _, host, path = url.split('/', 3)
    h = connections.get((scheme, host))
    if h and select.select([h.sock], [], [], 0)[0]:
        h.close()
        h = None
    if not h:
        Connection = HTTPConnection if scheme == 'http:' else HTTPSConnection
        h = connections[(scheme, host)] = Connection(host, **kwargs)
    h.request(method, '/' + path, body, headers)
    return h.getresponse()


def urlopen(url, data=None, *args, **kwargs):
    resp = request('POST' if data else 'GET', url, data, *args, **kwargs)
    assert resp.status < 400, (resp.status, resp.reason, resp.read())
    return resp

如何使用urllib在Python3.2中使用HTTP“Keep-Alive”

2 个答案: