你能解释一下这个快速排序方法吗?我正在尝试将此代码实现到我的程序中,但作者没有解释它的作用或它是如何做到的。还要注意我在高中,所以请尽量让它理解。
我所知道的是它快速排序2-D阵列。我也知道它使用递归来执行它的快速排序。不幸的是,就是这样。任何帮助将不胜感激。
public double[][] quicksort(double[][] array, int key, int down, int top) {
double[][] a = new double[array.length][2];
System.arraycopy(array, 0, a, 0, a.length);
int i = down;
int j = top;
double x = a[(down + top) / 2][key];
do {
while (a[i][key] < x) {
i++;
}
while (a[j][key] > x) {
j--;
}
if (i <= j) {
double[] temp = new double[a[i].length];
for (int y = 0; y < a[i].length; y++) {
temp[y] = a[i][y];
a[i][y] = a[j][y];
a[j][y] = temp[y];
}
i++;
j--;
}
} while (i <= j);
if (down < j) {
a = quicksort(a, key, down, j);
}
if (i < top) {
a = quicksort(a, key, i, top);
}
return a;
}
}
答案 0 :(得分:0)
要了解的几件事:
array
是键值对的数组,按键排序。
此快速排序返回原始数组的副本,而不是更改现有数组。
见评论:
public double[][] quicksort(double[][] array, int key, int down, int top) {
//create copy of array (the author wanted to return a new one)
double[][] a = new double[array.length][2];
System.arraycopy(array, 0, a, 0, a.length);
int i = down; //lower limit
int j = top; //upper limit
double x = a[(down + top) / 2][key]; //the pivot
do {
while (a[i][key] < x) { //skip over smaller elements in beginning
i++;
}
while (a[j][key] > x) { //skip over larger elements in end
j--;
}
//now do some partitioning
if (i <= j) {
//create temporary array, for swapping elements
double[] temp = new double[a[i].length];
for (int y = 0; y < a[i].length; y++) {
temp[y] = a[i][y];
a[i][y] = a[j][y];
a[j][y] = temp[y];
}
i++;
j--;
}
} while (i <= j);
//if there is a non-empty lower partition, sort that
if (down < j) {
a = quicksort(a, key, down, j);
}
//if there is a non-empty upper partition, sort that
if (i < top) {
a = quicksort(a, key, i, top);
}
//return the result
return a;
}
}