我有一个非常特别的设置:我用Java创建所有类,在我的应用程序中连接它们(几个ManyToOne关系)。
然后,我想迭代我的对象并将它们保存到数据库中。有时,对象已经在数据库中,因此不应再次持久化。
我实现了hashCode()和equals() - 方法正确,但我的em.merge()仍然插入了对象。
再次:
我创建了一些对象,即我创建了一些玩家并设置了他们所在的团队。团队可能是Java中的不同对象,但根据他们的“等于”方法,它们是相同的。因此,如果我保存一个玩家,团队应该相应地保存(这是有效的),但如果团队存在于数据库中(根据equals-method),则不应再次插入,但应设置关系,当然。
我做错了什么?需要更多信息?
private static void saveModels(final Set<?> models) {
EntityManagerFactory factory = null;
factory = Persistence.createEntityManagerFactory("sqlite");
EntityManager manager = factory.createEntityManager();
manager.getTransaction().begin();
for (Object object : models) {
manager.merge(object);
}
manager.getTransaction().commit();
manager.close();
factory.close();
}
修改
@Entity
public class Team {
private long id;
private String description;
@Id
@GeneratedValue
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description= description;
}
/*
* (non-Javadoc)
*
* @see java.lang.Object#hashCode()
*/
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + description.length();
return result;
}
/*
* (non-Javadoc)
*
* @see java.lang.Object#equals(java.lang.Object)
*/
@Override
public boolean equals(final Object obj) {
if (this == obj) {
return true;
}
if (obj == null) {
return false;
}
if (getClass() != obj.getClass()) {
return false;
}
Team other = (Team) obj;
if (!description.equals(other.getDescription())) {
return false;
}
return true;
}
}
@Entity
public class Player {
private long id;
private Team team;
private String name;
@Id
@GeneratedValue
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
@ManyToOne(cascade = { CascadeType.PERSIST, CascadeType.MERGE }, targetEntity = Team.class)
@JoinColumn(name = "team_id")
public Team getTeam() {
return team;
}
public void setTeam(Team team) {
this.team = team;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Override
public int hashCode() {
return name.length();
}
@Override
public boolean equals(Object obj) {
if (!(obj instanceof Player)) {
return false;
}
Player other = (Player) obj;
return other.getName().equals(name);
}
}
答案 0 :(得分:4)
JPA使用@Id字段进行合并,它不会使用equals和hashCode方法来检查数据库中是否已存在实体。
在团队中添加@OneToMany映射,就像Bozho建议的那样,虽然我会这样做。
@OneToMany(cascade = { CascadeType.ALL })
private List<Player> players = new ArrayList<Player>();
public void addPlayer(Player player) {
player.setTeam(this);
players.add(player);
}
public Collection<Player> getPlayers() {
return new ArrayList<Player>(this.players);
}
当你正在合并大量的entites时,我假设你正在从CSV或其他东西进行批量导入。然后,不是为CSV中的每一行创建一个新的团队/玩家,而是保持一个由名称键入的团队地图,并将玩家添加到相关团队。
所以,而不是
Team t = new Team();
t.setName(teamName)
Player p = new Player();
p.setName(playerName);
p.setTeam(t);
待办事项
Map<String, Team> teams = new HashMap<String,Team>();
...
if (!teams.containsKey(teamName)) {
Team t = new Team();
t.setDescription(teamName);
teams.put(teamName, t)
}
Player p = new Player();
p.setName(p);
teams.get(teamName).addPlayer(p);
...
saveModels(teams.values());
答案 1 :(得分:0)
通过将Team类作为一个字段集合给玩家来尝试使关系双向。这将注释如此
@OneToMany(cascade = { CascadeType.PERSIST, CascadeType.MERGE }, targetEntity = Team.class)
Collection<Player> getPlayers() {
return this.players;
}