您好我是Matlab的新手......我正在尝试不使用histeq进行直方图均衡...
但由于某种原因,我总是得到一个错误:???指数超过矩阵维度。
这是我的代码........................................... .......感谢您的帮助
clc
I = imread ('Machine-Edge.PNG');
I2 = rgb2gray(I);
colormap gray;
y = imhist(I2);
%using hist eq. built in fn
I3= histeq(I2);
z= imhist(I3);
%my equalization
r = size(I2,1);
c = size(I2,2);
A= zeros(1,256);
%counting number of pixels of the image and putting the count in Array A
for j=1:r
for x=1:c
v=I2(j,x);
A(v+1)=A(v+1)+1;
end
end
%pi=n/size
for y=1;256
pi(y)= ((A(y))/(r*c));
end
%calculate CI (cumulated pi )
ci(1)=pi(1);
for yy=2;256
ci(yy) = ci(yy-1)+ pi(yy);
end
%calculate T=range *Ci
for b=1;256
T(b)=ci(b)*255;
end
%equilization..replacing each pixel with T value
for j=1:r
for x=1:c
I4(j,x) =T(I2(j,x));
end
end
vv= imhist(I4);
figure
subplot(3,2,1)
imagesc(I2)
subplot(3,2,2)
plot(y)
subplot(3,2,3)
imagesc(I3)
subplot(3,2,4)
plot(z)
subplot(3,2,5)
imagesc(I4)
subplot(3,2,6)
plot(vv)
答案 0 :(得分:0)
这是一个老帖子,但OP使用;而不是:在它们的for循环中(即对于y = 1; 256应该读取y = 1:256)。更正后的代码如下:
clc
I = imread ('Machine-Edge.PNG');
I2 = rgb2gray(I);
colormap gray;
y = imhist(I2);
%using hist eq. built in fn
I3= histeq(I2);
z= imhist(I3);
%my equalization
r = size(I2,1);
c = size(I2,2);
A= zeros(1,256);
%counting number of pixels of the image and putting the count in Array A
for j=1:r
for x=1:c
v=I2(j,x);
A(v+1)=A(v+1)+1;
end
end
%pi=n/size
for y=1:256
pi(y)= ((A(y))/(r*c));
end
%calculate CI (cumulated pi )
ci(1)=pi(1);
for yy=2:256
ci(yy) = ci(yy-1)+ pi(yy);
end
%calculate T=range *Ci
for b=1:256
T(b)=ci(b)*255;
end
%equilization..replacing each pixel with T value
for j=1:r
for x=1:c
I4(j,x) =T(I2(j,x));
end
end
vv= imhist(I4);
figure
subplot(3,2,1)
imagesc(I2)
subplot(3,2,2)
plot(y)
subplot(3,2,3)
imagesc(I3)
subplot(3,2,4)
plot(z)
subplot(3,2,5)
imagesc(I4)
subplot(3,2,6)
plot(vv)