如何生成两个随机数（不重复）？

Question

我想在java中生成两个数字，范围为0..99，并且不得重复。我试过下面的代码，但它对我不起作用。

    int number1 = randomGenerator.nextInt(100);
    int number2 = randomGenerator.nextInt(100);

    if(number1 == number2){
        while (number1 != number2){
            number2 = randomGenerator.nextInt(100);
        }
    }

Answer 1

如果number1和number2相等，则不相等。只需更改while循环：

int number1 = randomGenerator.nextInt(100);
int number2 = randomGenerator.nextInt(100);

while(number1 == number2){
    number2 = randomGenerator.nextInt(100);
}

Answer 2

它不起作用，因为你从不进入循环，因为条件错误。在循环中，您需要==，而不是!=。您也可以删除if：

int number1 = randomGenerator.nextInt(100);
int number2 = randomGenerator.nextInt(100);

while (number1 == number2){
    number2 = randomGenerator.nextInt(100);
}

Answer 3

int number1 = randomGenerator.nextInt(100);
int number2 = randomGenerator.nextInt(99);
if(number2 >= number1) {
  ++number2;
}

同时在Generate random index different then any one given in a set

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Answer 4

如果它们都必须是唯一的，则应将结果添加到列表中。然后，您可以将当前随机数与过去的每个结果进行比较。

    Random random = new Random();
    int number1 = random.nextInt(100);
    int number2 = random.nextInt(100);
    List<Integer> randomsList = new ArrayList<Integer>();

    while (randomsList.contains(number1)){
        number1 = random.nextInt(100);
    }
    randomsList.add(number1);

    while (randomsList.contains(number2)){
        number2 = random.nextInt(100);
    }
    randomsList.add(number2);