import java.awt.*;
import java.awt.geom.Line2D;
import java.awt.geom.Point2D;
import java.awt.geom.Rectangle2D;
import java.applet.Applet;
import java.util.Scanner;
public class Histogram extends Applet{
static int [] scores= {13,30,23,8};
static int [] minInterval = {0,25,50,75};
static int [] maxInterval = {25,50,75,100};
public void paint (Graphics g){
int max = 0;
for (int i = 0; i < scores.length; i++) {
if (max < scores[i]) {
max = scores[i];
}
}
Graphics2D g2 = (Graphics2D)g;
Point2D.Double Yi = new Point2D.Double(50,50);
Point2D.Double Yf = new Point2D.Double(50,30*scores.length);
Line2D.Double Y = new Line2D.Double (Yi,Yf);
Point2D.Double Xi = new Point2D.Double(50,50);
Point2D.Double Xf = new Point2D.Double(50+(8*max),50);
Line2D.Double X = new Line2D.Double (Xi,Xf);
int x = 8*max;
//Draw the "Score"
int headerX = 50+(x/(max/5))*((max/5)-1);
g2.drawString("Histogram of Student Scores",(headerX),30);
for(int i=0;i<=max/5;i++){
int j = (i)*5;
if(i<max/5)
g2.drawString(String.format("%d",j),50+(x/(max/5))*i,50);
else
g2.drawString(String.format("Number of Students"),50+(x/(max/5))*i,50);
}
for(int i=0;i<=maxInterval.length;i++){
if(i != maxInterval.length-1 )
g2.drawString(String.format("[%d,%d)",minInterval,maxInterval),20,60+(30)*i);
else if(i == maxInterval.length-1)
g2.drawString(String.format("[%d,%d]",minInterval,maxInterval),20,60+(30)*i);
else
g2.drawString("Score Ranges",20,60+(30)*i);
}
g2.draw(X);
g2.draw(Y);
}
}
我的问题是代码没有进入第三个循环。但是当我在另一个循环中测试循环时
方法。它有点工作。所以我不知道接下来该做什么。我想知道它为什么没有
执行该代码块。
提前谢谢。
答案 0 :(得分:0)
您将一个数组作为参数提供给String.format("...", , )
(而不是int
,您可以通过查找数组中的元素(可能是索引i
)来获得。< / p>
因为它是String.format的参数,所以很可能没有得到编译器或IDE警告。
因此,如果你修复了这个问题,那么代码就像这样,你可以从那里开始。
for (int i = 0; i <= maxInterval.length; i++) {
if (i != maxInterval.length - 1)
g2.drawString(String.format("[%d,%d]", minInterval[i], maxInterval[i]), 20, 60 + (30) * i);
else if (i == maxInterval.length - 1)
g2.drawString(String.format("[%d,%d]", minInterval[i], maxInterval[i]), 20, 60 + (30) * i);
else
g2.drawString("Score Ranges", 20, 60 + (30) * i);
}