我的代码编译得很好但是当我运行它时我得到总线错误:10
void backupf(char *namelist, char *dirname)
{
char *in_filename;
char *out_filename;
char line[MAXPATHLEN];
FILE *filenames = fopen(namelist, "r");
if(filenames == NULL)
{
fprintf(stderr, "Cannot Open File\n");
exit(EXIT_FAILURE);
}
while( fgets(line, sizeof line, filenames) != NULL )
{
sprintf(in_filename, "./%s\n", line);
sprintf(out_filename, "%s/%s\n", dirname, line);
}
backup(dirname, in_filename, out_filename);
fclose(filenames);
}
应该使用带有文件名列表的文本文件参数,然后使用该信息使用我编写的备份函数将其备份到备份目录。
答案 0 :(得分:1)
您没有为文件名分配空间;你应该。你在写不确定的记忆。这可能会更好:
void backupf(char *namelist, char *dirname)
{
char in_filename[MAXPATHLEN];
char out_filename[MAXPATHLEN];
char line[MAXPATHLEN];
FILE *filenames = fopen(namelist, "r");
if (filenames == NULL)
{
fprintf(stderr, "Cannot Open File\n");
exit(EXIT_FAILURE);
}
while (fgets(line, sizeof(line), filenames) != NULL)
{
snprintf(in_filename, sizeof(in_filename)"./%s\n", line);
snprintf(out_filename, sizeof(out_filename), "%s/%s\n", dirname, line);
backup(dirname, in_filename, out_filename);
}
fclose(filenames);
}