需要帮助修改“stock”php / mysql dreamweaver代码

时间:2009-12-29 05:49:01

标签: php mysql

我正在使用dreamweaver cs4“插入”功能来管理单个页面上的多个表单。但我编辑代码时遇到困难:

  1. 将表单中的数据插入表格
  2. 检索新添加的行的ID
  3. 在同一页面上回显确认消息,并在包含id(作为参考)
  4. 的链接上回显

    这是Dreamweaver到目前为止给我的内容......它应该只向数据库添加一个新行(未经测试):

    <?php
    if (!function_exists("GetSQLValueString")) {
    function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") 
    {
      if (PHP_VERSION < 6) {
        $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
      }
    
      $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);
    
      switch ($theType) {
        case "text":
          $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
          break;    
        case "long":
        case "int":
          $theValue = ($theValue != "") ? intval($theValue) : "NULL";
          break;
        case "double":
          $theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
          break;
        case "date":
          $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
          break;
        case "defined":
          $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
          break;
      }
      return $theValue;
    }
    }
    
    $editFormAction = $_SERVER['PHP_SELF'];
    if (isset($_SERVER['QUERY_STRING'])) {
      $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']);
    }
    
    if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form")) {
      $insertSQL = sprintf("INSERT INTO tbl_solicitors (solicitorName, solicitorDetail) VALUES (%s, %s)",
                           GetSQLValueString($_POST['solicitorName'], "text"),
                           GetSQLValueString($_POST['solicitorDetail'], "text"));
    
      mysql_select_db($database_speedycms, $speedycms);
      $Result1 = mysql_query($insertSQL, $speedycms) or die(mysql_error());
    }
    ?>
    

    任何帮助将不胜感激...谢谢,新年快乐!

1 个答案:

答案 0 :(得分:0)

不要担心我找到了解决方案......决定不使用我不熟悉的代码!

感谢您查看!

if (array_key_exists('solicitor',$_POST)) {
            $solicitorName = $_POST['solicitorName'];
            echo "The record for <b>$solicitorName</b> has been successfully added to the database.<p>
            <a href='#' class='form'>View details</a><p>
            <a href='instructus.php' class='form'>Create a new record</a>
            ";
            exit;
            };