Question

在尝试自己做一些调试后找出问题

我发现@cols和@cols2变量没有带来结果，我有PRINT

PRINT('INSERT INTO [' + @Destination_Database_Name + '].[dbo].[' + @tablename + '] (' + @cols2 + ']' + ') SELECT [' + @cols2 + ']' + ' FROM [' + @Source_Database_Name + '].[dbo].[' + @tablename + ']');

声明不会显示我得到的输出

（1行受影响）

（1行（s）受影响）我在这里2

c365online_script1 我在这里3 tCompany

这是我认为是问题的代码部分

   Print 'I am here2'
                        SET IDENTITY_INSERT c365online_script1.dbo.tCompany ON
                        declare @cols2 varchar(max)
                        PRINT @cols2
                        select @cols2 = (Select Stuff((Select '],[' + C.COLUMN_NAME From INFORMATION_SCHEMA.COLUMNS As C Where C.TABLE_SCHEMA = T.TABLE_SCHEMA And C.TABLE_NAME = T.TABLE_NAME Order By C.ORDINAL_POSITION For Xml Path('')), 1, 2, '') As Columns From INFORMATION_SCHEMA.TABLES As T WHERE T.TABLE_NAME = @tablename)
                        PRINT('INSERT INTO [' + @Destination_Database_Name + '].[dbo].[' + @tablename + '] (' + @cols2 + ']' + ') SELECT [' + @cols2 + ']' + ' FROM [' + @Source_Database_Name + '].[dbo].[' + @tablename + ']');
                        PRINT @Destination_Database_Name
                         Print 'I am here3'
                         Print @tablename
                    END

我可以根据要求发布完整的代码

Answer 1

尝试

SET @cols2 = (Select....)

而不是

SELECT @cols2 = (Select....)

Answer 2

这是一个NULL连接问题。尝试将变量初始化为空字符串，如下所示，并查看您对查询结果的了解：

    declare @tablename varchar(128) = '', 
            @Destination_Database_Name varchar(128) = '', 
            @Source_Database_Name varchar(128) = '';

sql动态变量没有执行？

2 个答案: