Question

我想用java制作游戏。游戏是记忆游戏，在游戏开始时显示所有牌，然后点击时翻转所有牌，然后每次点击它一次显示一张牌。

如果2张牌相同则仍然可见
如果两张牌不一样，他们会翻回来

我只有2周大的Java观点，所以请尽量保持清晰。

这是我实现了这样的票价而且当我点击时我被卡住翻了。

我使用处理库。任何帮助，将不胜感激。

package cards;
import processing.core.PApplet;
public class MemoryGame extends PApplet {

Card[] cards;

public void setup() {
    size(1260, 600); 
    cards = new Card[6];
    cards[0] = new Card(11, 0, 0);
    cards[1] = new Card(3, Card.WIDTH, 0);
    cards[2] = new Card(7, 2 * Card.WIDTH, 0);
    cards[3] = new Card(3, 0, Card.HEIGHT);
    cards[4] = new Card(7, Card.WIDTH, Card.HEIGHT);
    cards[5] = new Card(11, 2 * Card.WIDTH, Card.HEIGHT);

}

public void draw() {
    background(204);
    for (int i = 0; i < 6; i++) {
        cards[i].display(this);
    }
}

public void mousePressed() {
         for (int i = 0; i < 6; i++) {
        cards[i].display(this);
    }
             }

public static void main(String[] args) {
    PApplet.main("cards.MemoryGame");
}
}

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ ++

package cards;

import processing.core.PApplet;

public class Card {

boolean shown=false;
static final int WIDTH = 120;
static final int HEIGHT = 180;
static final int gap = 20;
int value;
float x;
float y;

Card(int _v, float _x, float _y) {

    value = _v;
    x = _x;
    y = _y;
}

public void display(PApplet applet) {
    if (shown) {
        applet.fill(0);
        applet.rect(x, y, WIDTH, HEIGHT);
    } else {
        applet.fill(255);
        applet.rect(x, y, WIDTH, HEIGHT);
    }
}

public void flip() {
    shown=!shown;
}
}

Answer 1

将mousePressed（）更改为：

public void mousePressed() {
         for (int i = 0; i < 6; i++) {
        //first flip cards
        cards[i].flip();

        //then display them
        cards[i].display(this);
    }

Java记忆游戏

1 个答案: