我有两个实体AddressEntity
和CompanyEntity
。
地址实体
@Entity
@Table(name = "address")
public class AddressEntity implements Serializable {
private static final long serialVersionUID = 6149442393833549397L;
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private Integer id;
@Column(name = "city", nullable = false)
private String city;
@Column(name = "post")
private String post;
@Column(name = "street", nullable = false)
private String street;
@Column(name = "building_nr", nullable = false)
private Integer buildingNr;
@Column(name = "flat_nr")
private Integer flatNr;
// setters and getters
}
公司实体
@Entity
@Table(name = "company")
public class CompanyEntity implements Serializable {
private static final long serialVersionUID = 3635072833730133590L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id")
private Integer id;
@Column(name = "name")
private String name;
@OneToOne
@Cascade(CascadeType.ALL)
private AddressEntity address = new AddressEntity();
@OneToMany(mappedBy = "company")
@Cascade(CascadeType.ALL)
private Set<DescriptionEntity> descriptions = new HashSet<DescriptionEntity>();
@OneToMany(mappedBy = "company")
@Cascade(CascadeType.ALL)
private List<EmployeeEntity> employees = new ArrayList<EmployeeEntity>();
}
我希望select all addresses which are used by companies
喜欢这个SQL查询SELECT a.city, c.name FROM address a INNER JOIN company c ON c.address_id=a.id;
但是使用HQL查询(我想使用JOIN,而不是WHERE)。我该怎么做?我想使用地址表选择地址,而不是公司表。我知道我可以使用像select c.address.city, c.name from CompanyEntity c
这样的公司表或使用WHERE select a.city, c.name from CompanyEntity c, AddressEntity a WHERE c.address.id=a.id
来选择地址。
答案 0 :(得分:1)
Criteria c = session.createCriteria(CompanyEntity.class);
c.createAlias("address", "address");
List<CompanyEntity> companies = c.list();
这将为您提供至少有CompanyEntities
个AddressEntity
的列表。
如果添加以下行:
c.criteria.setProjection(Projections.property("address"));
您可以通过AddressEntities
获得c.list()
的列表。
告诉我你是否需要别的东西。