Question

我试图显示两个日期之间created_at日期的行数。

这是我的代码：

$result=mysql_query("select * from payments 
                     where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'") 
                     or die('You need to add an administrator ' );

$counter = mysql_query("select * from payments 
                        where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'");

$row = mysql_fetch_array($result);

$id = $row['id'];

$num = mysql_fetch_array($counter);
$countjan = $num["id"];

然而，当我回应

<?php echo"$jan";?>

这显示为0我知道如何让这个工作

P.s在此日期范围内有1行

Answer 1

您可以这样查询：

SELECT COUNT(*) FROM your_table WHERE created_at >= '2013/10/01 00:00:00' AND created_at <= '2013/10/30 00:00:00'

BTW：您应该使用MySQL日期格式或时间戳。

Answer 2

试试这个

$res=mysql_query("SELECT * FROM your_table WHERE created_at >= '2013/10/01 00:00:00' AND created_at <= '2013/10/30 00:00:00'");
if($res)
{
$count=mysql_num_rows($res);
echo $count;
}

Answer 3

SELECT COUNT(*) FROM your_table WHERE created_at >= '2013/10/01 00:00:00' AND created_at <= '2013/10/30 00:00:00'

显示2个日期之间的行数

3 个答案: