Question

我试图了解Mongo的整个聚合框架。我在这里是个新手。

 I have the following documents:
 { "col1": "camera", "fps": 1, "lat": 3 },
 { "col1": "camera", "fps": 3, "lat": 2 }
 { "col1": "recorders", "fps": 9, "lat": 7 }
 { "col1": "cell", "fps": 8, "lat": 1 }
 { "col1": "cell", "fps": 4, "lat": 3 }

如何设置一些内容以将结果返回为：

 { "col1": "camera", "fps": 4, "lat": 5 },
 { "col1": "recorders", "fps": 9, "lat": 7 },
 { "col1": "cell", "fps": 12, "lat": 4 },

由于

Answer 1

db.yourCollection.aggregate(
    { $group : {
        _id : "$col1",
        fps : { $sum : "$fps" },
        lat : { $sum : "$lat" }
    }}
);

检查出来!!! http://docs.mongodb.org/manual/reference/operator/aggregation/group/

Answer 2

我认为这应该可以解决问题：

db.collectionName.aggregate(
    { $group: { _id: "$col1", fps: { $sum: "$fps" }, lat: { $sum: "$lat" }}}
)

聚合/分组与总和

2 个答案: