Question

编写脚本以读取正整数，然后计算以下序列：如果数字是偶数，则将其减半如果它是奇数乘以3并且加1

您应该重复此过程，直到值为1，打印出每个值以及您执行的这些操作的数量。

#! bin\csh

echo "please enter any integer number :) "

set count=0

set number=$<

while($number != 1)

   if($number % 2) then

       @ number = number * 3 + 1 

   else

       @ number = number / 2

   endif

   echo " $number "

   @ count = count ++

end

echo I performed these operations $count times

当我运行脚本时，我收到以下错误： @: Expression Syntax.

Answer 1

我相信它的$ variable来获取它的值

$
    Obtains the value of the variable. 

@ var = $a + $x * $z

来源http://www.eng.hawaii.edu/Tutor/csh.html

那就是

@count = $count +1

行

#!bin\csh

让我颤抖

Answer 2

我得到了正确的解决方案：）

#! /bin/csh

echo "please enter any integer number :) "

set count=0

set inc=1

set number=$<

while($number != 1)

   if($number % 2) then

       @ number = $number * 3 + 1 

   else

       @ number = $number / 2

   endif

   @ count = $count + $inc

   echo " $number "


end

echo I performed these operations $count times

Shell脚本中的语法错误

2 个答案: