我有一个包含以下代码的程序:
Dim Var1 as string = textbox1.text
Dim Var2 as string = textbox2.text
Dim Var3 as string = textbox3.text
Dim EndVar as string = Var1 + Var2 + Var3
让我们假设用户为三个文本框变量输入1,2和3,我希望EndVar等于6,但它给了我123.如何让它给我6?
答案 0 :(得分:0)
你可以将它们中的每一个转换为int,求它们然后将它转换回字符串:
Dim EndVar as string = (Convert.toInt32(Var1) + Convert.toInt32(Var2) + Convert.toInt32(Var3)).ToString();
答案 1 :(得分:0)
System.Convert.To ......无论你需要什么...... 看看这个http://msdn.microsoft.com/en-us/library/sf1aw27b.aspx?cs-save-lang=1&cs-lang=vb#code-snippet-2
Dim values() As String = { "One", "1.34e28", "-26.87", "-18", "-6.00", _
" 0", "137", "1601.9", Int32.MaxValue.ToString() }
Dim result As Integer
For Each value As String In values
Try
result = Convert.ToInt32(value)
Console.WriteLine("Converted the {0} value '{1}' to the {2} value {3}.", _
value.GetType().Name, value, result.GetType().Name, result)
Catch e As OverflowException
Console.WriteLine("{0} is outside the range of the Int32 type.", value)
Catch e As FormatException
Console.WriteLine("The {0} value '{1}' is not in a recognizable format.", _
value.GetType().Name, value)
End Try
Next
' The example displays the following output:
' The String value 'One' is not in a recognizable format.
' The String value '1.34e28' is not in a recognizable format.
' The String value '-26.87' is not in a recognizable format.
' Converted the String value '-18' to the Int32 value -18.
' The String value '-6.00' is not in a recognizable format.
' Converted the String value ' 0' to the Int32 value 0.
' Converted the String value '137' to the Int32 value 137.
' The String value '1601.9' is not in a recognizable format.
' Converted the String value '2147483647' to the Int32 value 2147483647.