我试图找出为什么Codeigniter在我的数据库中插入相同行的2倍。我正在使用PDO作为mySQL的接口。我正在调试它,我确信下面的函数没有被执行两次。它发生在特定情况下,如果两个foreache因为数组为空而没有运行,但是如果其中一个运行错误就不会发生。
`
public function save_all() //save all information with the launched flag FALSE
{
include(database_vars_url());
try
{
$this->add_new_skills();
if(!isset($_SESSION))
{
session_start();
}
$email = $_SESSION["email"];
$sql = "INSERT INTO $tbl_name_contest (user_id, contest_title, contest_overview, contest_description,
contest_category, contest_holder, contest_prize, contest_stage, contest_duration, contest_proj_duration,
contest_level, contest_finalist, contest_winner, contest_create, contest_launched, contest_edit,
contest_edit_id, contest_status, contest_delete)
VALUES (0, '$this->title', '$this->overview', '$this->description', '$this->category',
(SELECT customer_id FROM $tbl_name_customer WHERE user_id =
(SELECT user_id FROM $tbl_name_user WHERE user_email='$email')), '$this->prize', 0, '$this->contest_period',
'$this->project_period', -1, -1, -1, NULL, DEFAULT, NULL, -1, -1, DEFAULT); ";
foreach ($this->addon as $value)
{
$sql = $sql . "INSERT INTO $tbl_rel_contest_addon (add_contest_id, add_addon_id)
VALUES ((SELECT contest_id FROM $tbl_name_contest WHERE contest_title = '$this->title'
AND contest_overview = '$this->overview' AND contest_prize = '$this->prize'),
(SELECT addon_id FROM $tbl_name_addon WHERE addon_name = '$value')); ";
}
foreach ($this->skills as $value)
{
$sql = $sql . "INSERT INTO $tbl_rel_contest_skill (required_contest_id, required_skill_id)
VALUES ((SELECT contest_id FROM $tbl_name_contest WHERE contest_title = '$this->title'
AND contest_overview = '$this->overview' AND contest_prize = '$this->prize'),
(SELECT skill_id FROM $tbl_name_skill WHERE skill_name = '$value')); ";
}
echo $sql;
return $this->db->query($sql);
}
catch(Exception $e)
{
echo $e->getMessage();
}
return 0;
}
这里我有一个mySQL的日志,前两个SELECTS被“$ this-> add_new_skills();”调用在函数save_all()的开头。这些SELECT也应该只是一个。这个命令SELECT SELECT,INSERT INSERT,证明函数save_all()没有被调用两次,如果它被调用两次,那么顺序就是SELECT INSERT SELECT INSERT。
138 Connect root@localhost on repsero
138 Query SELECT skill_name FROM skill WHERE skill_status=2
138 Query SELECT skill_name FROM skill WHERE skill_status=2
138 Quit
139 Connect root@localhost on repsero
139 Quit
140 Connect root@localhost on repsero
140 Query INSERT INTO contest (user_id, contest_title, contest_overview, contest_description, contest_category, contest_holder, contest_prize, contest_stage, contest_duration, contest_proj_duration, contest_level, contest_finalist, contest_winner, contest_create, contest_launched, contest_edit, contest_edit_id, contest_status, contest_delete) VALUES (0, 'Contest Name', 'Overview of the contest Overview of the contest Overview of the contest Overview of the contest Overview of the contest Overview of the contest ', 'Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description ', 'SEO', (SELECT customer_id FROM customer WHERE user_id = (SELECT user_id FROM user WHERE user_email='customer@repsero.com')), '300', 0, '5','1', -1, -1, -1, NULL, DEFAULT, NULL, -1, -1, DEFAULT)
140 Query INSERT INTO contest (user_id, contest_title, contest_overview, contest_description, contest_category, contest_holder, contest_prize, contest_stage, contest_duration, contest_proj_duration, contest_level, contest_finalist, contest_winner, contest_create, contest_launched, contest_edit, contest_edit_id, contest_status, contest_delete) VALUES (0, 'Contest Name', 'Overview of the contest Overview of the contest Overview of the contest Overview of the contest Overview of the contest Overview of the contest ', 'Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description Description ', 'SEO',(SELECT customer_id FROM customer WHERE user_id = (SELECT user_id FROM user WHERE user_email='customer@repsero.com')), '300', 0, '5', '1', -1, -1, -1, NULL, DEFAULT, NULL, -1, -1, DEFAULT)
140 Quit
答案 0 :(得分:2)
好吧,我发现codeigniter系统里面的CI_DB_pdo_driver中的_execute()函数运行不正常,可能是因为php版本。无论如何,我改变了CodeIgniter的代码:
function _execute($sql)
{
$sql = $this->_prep_query($sql);
$result_id = $this->conn_id->prepare($sql);
$result_id->execute();
if (is_object($result_id))
{
if (is_numeric(stripos($sql, 'SELECT')))
{
$this->affect_rows = count($result_id->fetchAll());
$result_id->execute();
}
else
{
$this->affect_rows = $result_id->rowCount();
}
}
else
{
$this->affect_rows = 0;
}
return $result_id;
}
TO:
function _execute($sql)
{
$sql = $this->_prep_query($sql);
$result_id = $this->conn_id->prepare($sql);
$result_id->execute();
if (is_object($result_id))
{
if (preg_match('/^\s*"?(SELECT)\s+/i', $sql))
{
$this->affect_rows = count($result_id->fetchAll());
$result_id->execute();
}
else
{
$this->affect_rows = $result_id->rowCount();
}
}
else
{
$this->affect_rows = 0;
}
return $result_id;
}
测试$ sql中是否包含“SELECT”的部分无法正常工作,因此当我尝试INSERT时,“$ result_id-> execute()”被调用了两次。