Question

跟踪我的项目扫描程序，这是一个扫描* .txt文件目录的java工具。

谢谢大家的帮助！但是现在我有一个不同的问题。

当我得到结果时，它会读取我不希望它读取的字符串。如何阻止这些字符串我不想读它？

这就是我的意思：

Enter item to find: 1112
Found   125000000

[BANK]

[FRIENDS]

[IGNORES]

[EOF]

 time(s) in kyle.txt!
Found   1000000

[FRIENDS]

[IGNORES]

[EOF]

 time(s) in kylea.txt!
Press any key to continue . . .

我希望它显示如下结果：

Enter item to find: 1112
Found 125000000 time(s) in kyle.txt!
Found 1000000 time(s) in kylea.txt!
Press any key to continue . . .

我该怎么做？我尝试创建一个数组列表来阻止我不需要的其他结果，但我也无法让它工作。

感谢您的帮助！

此外，这是我的代码：

import java.io.*;
import java.util.*;

public class ItemScanner {

public static void main(String args[]) {

    System.out.print("Enter item to find: ");
    Scanner sc = new Scanner(System.in);
    find(sc.nextLine());
}

public static void find(String delim) {
    File dir = new File("accounts");
    if (dir.exists()) {
        String read;
        try {
            File files[] = dir.listFiles();
            for (int i = 0; i < files.length; i++) {
                File loaded = files[i];
                if (loaded.getName().endsWith(".txt")) {
                    BufferedReader in = new BufferedReader(new FileReader(loaded));
                    StringBuffer load = new StringBuffer();
                    while ((read = in.readLine()) != null) {
                        load.append(read + "\n");
                    }
                    String delimiter[] = new String(load).split(delim);

                    if(delimiter.length > 1) {
                    System.out.println("Found " + (delimiter[1]) + " time(s) in " +       loaded.getName() + "!");
                    }
                }
            }  
        } catch (Exception e) {
            e.printStackTrace();
        }
    } else {
        System.out.println("error: dir wasn't found!");
    }
}
}

此外，它扫描的帐户示例如下：

[ACCOUNT]
character-username = kylea
character-password = 

[CHARACTER]
character-height = 0
character-isactive = 1
character-messages = 0
character-lastconnection = 
character-lastlogin = 2009/11/27
character-energy = 100

[EQUIPMENT]
character-equip = 0     4724    0   
character-equip = 1     1052    0   
character-equip = 2     6585    0   
character-equip = 3     4151    0   
character-equip = 4     4720    0   
character-equip = 5     1215    0   
character-equip = 6     -1  0   
character-equip = 7     4722    0   
character-equip = 8     -1  0   
character-equip = 9     775 0   
character-equip = 10    1837    0   
character-equip = 11    -1  0   
character-equip = 12    6735    0   
character-equip = 13    -1  0   

[LOOK]
character-look = 0      1

[SKILLS]
character-skill = 0     18  445633
character-skill = 1     15  440000
character-skill = 2     15  440000
character-skill = 3     199 1402300000
character-skill = 4     22  0
character-skill = 5     1   0
character-skill = 6     1   0
character-skill = 7     1   0
character-skill = 8     1   0
character-skill = 9     1   0
character-skill = 10    1   0
character-skill = 11    1   0
character-skill = 12    1   0
character-skill = 13    1   0
character-skill = 14    1   0
character-skill = 15    1   0
character-skill = 16    1   0
character-skill = 17    1   0
character-skill = 18    1   0
character-skill = 19    1   0
character-skill = 20    1   0
character-skill = 21    1   0
character-skill = 22    1   0
character-skill = 23    1   0
character-skill = 24    1   0

[ITEMS]
character-item = 0      6570    11
character-item = 1      666570  0525
character-item = 2      1165701 55
character-item = 3      55  66
character-item = 4      963 51
character-item = 5      961 55

[BANK]
character-bank = 0      996 1000000

[FRIENDS]

[IGNORES]

[EOF]

Answer 1

您在此代码中正在执行的操作是读取字符串缓冲区中的.txt文件的内容，并在示例“1112”中将该文件内容拆分到分隔符上，然后打印该文件的其余部分。

所以，如果你的文件包含“aaaa11121112uh哦”它会打印“1112uh哦”？我不清楚你想要完成什么。

只显示数字的快速修复将使用：

Long.valueOf(delimiter[1])

仅解析剩余部分的数字部分并打印出来。我觉得这不会解决潜在的问题，所以也许你可以详细说明你想在这里实现的目标？

修改用一个数据文件的例子更新你的问题后，（看起来非常像.ini文件:-)）我认为通过阅读Properties class的javadoc，特别是{{{ 3}}和load()方法，将您的角色数据存储在Properties集合中。

Answer 2

您似乎混淆了一些示例代码。您似乎从问题和main（）中寻找特定项目，但在代码中，您使用传入参数作为分隔符来分割您读取的行，并计算单词数。

要执行您的问题所要求的问题，您需要使用逻辑来拆分读入行，然后迭代它，与要查找的项目进行比较。

仅显示找到的结果

2 个答案: