PHP Rookie在这里......
尝试将if / elseif语句放入我的php代码中以获取表单电子邮件。
如果用户选择“Sandy”,那么电子邮件应该转到Sandy的电子邮件地址。如果用户选择“Steve”发送给Steve的电子邮件地址等,这是我到目前为止的代码。任何建议表示赞赏。
<?php
require_once('phpmailer/class.phpmailer.php');
$mail = new PHPMailer();
if( isset( $_POST['template-contactform-submit'] ) AND $_POST['template-contactform-submit'] == 'submit' ) {
if( $_POST['template-contactform-name'] != '' AND $_POST['template-contactform-email'] != '' AND $_POST['template-contactform-subject'] != '' AND $_POST['template-contactform-message'] != '' ) {
$name = $_POST['template-contactform-name'];
$email = $_POST['template-contactform-email'];
$subject = $_POST['template-contactform-subject'];
$message = $_POST['template-contactform-message'];
$botcheck = $_POST['template-contactform-botcheck'];
if( $_POST['template-contactform-employee'] = 'Sandy' ):
{
$toemail = 'sandy@example.com';
$toname = 'Sandy';
}
elseif( $_POST['template-contactform-employee'] = 'Steve' ):
{
$toemail = 'steve@example.com';
$toname = 'Steve';
}
elseif( $_POST['template-contactform-employee'] = 'Nick' ):
{
$toemail = 'nick@example.com';
$toname = 'Nick';
}
else: {
$toemail = "support@example.com";
$toname = "Support";
}
endif;
$body = "$message";
if( $botcheck == '' ) {
$mail->SetFrom( $email , $name );
$mail->AddReplyTo( $email , $name );
$mail->AddAddress( $toemail , $toname );
$mail->Subject = $subject;
$mail->MsgHTML( $body );
$sendEmail = $mail->Send();
if( $sendEmail == true ):
echo '<div class="alert alert-success"><button type="button" class="close" data-dismiss="alert">×</button>We have <strong>successfully</strong> received your Message and will get Back to you as soon as possible.</div>';
else:
echo '<div class="alert alert-error"><button type="button" class="close" data-dismiss="alert">×</button>Email <strong>could not</strong> be sent due to some Unexpected Error. Please Try Again later.<br /><br /><strong>Reason:</strong><br />' . $mail->ErrorInfo . '</div>';
endif;
} else {
echo '<div class="alert alert-error"><button type="button" class="close" data-dismiss="alert">×</button>Bot <strong>Detected</strong>.! Clean yourself Botster.!</div>';
}
} else {
echo '<div class="alert alert-error"><button type="button" class="close" data-dismiss="alert">×</button>Please <strong>Fill up</strong> all the Fields and Try Again.</div>';
}
} else {
echo '<div class="alert alert-error"><button type="button" class="close" data-dismiss="alert">×</button>An <strong>unexpected error</strong> occured. Please Try Again later.</div>';
}
?>
答案 0 :(得分:1)
@andrewsi的解决方案有效。感谢您发现我的错误!
if( $_POST['template-contactform-employee'] = 'Sandy')
错误 - 您使用=
进行等级检查,而不是==
。试试if( $_POST['template-contactform-employee'] == 'Sandy')
,看看是否有所不同(你需要修改每条if行。)