Question

如何BindAttribute在控制器中包含或排除嵌套属性？

我有一个'Stream'模型：

public class Stream
{
    public int ID { get; set; }

    [Required]
    [StringLength(50, ErrorMessage = "Stream name cannot be longer than 50 characters.")]
    public string Name { get; set; }

    [Required]
    [DataType(DataType.Url)]
    public string URL { get; set; }

    [Required]
    [Display(Name="Service")]
    public int ServiceID { get; set; }

    public virtual Service Service { get; set; }
    public virtual ICollection<Event> Events { get; set; }
    public virtual ICollection<Monitor> Monitors { get; set; }
    public virtual ICollection<AlertRule> AlertRules { get; set; }
}

对于此模型的“创建”视图，我创建了一个视图模型以将一些其他信息传递给视图：

public class StreamCreateVM
{
    public Stream Stream { get; set; }
    public SelectList ServicesList { get; set; }
    public int SelectedService { get; set; }
}

这是我的创建后期操作：

    [HttpPost]
    [ValidateAntiForgeryToken]
    public ActionResult Create([Bind(Include="Stream, Stream.Name, Stream.ServiceID, SelectedService")] StreamCreateVM viewModel)
    {
        if (ModelState.IsValid)
        {
            db.Streams.Add(viewModel.Stream);
            db.SaveChanges();
            return RedirectToAction("Index", "Service", new { id = viewModel.Stream.ServiceID });
        }

        return View(viewModel);
    }

现在，除了[Bind(Include="Stream, Stream.Name, Stream.ServiceID, SelectedService")]位之外，这一切都有效。我似乎无法在嵌套对象中包含或排除属性。

Answer 1

根据this answer，您可以执行以下操作：

[Bind(Include="Name, ServiceID")]
public class Stream
{
...
}

然后

[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create([Bind(Include="Stream, SelectedService")] StreamCreateVM viewModel)
{
...
}

BindAttribute，排除复杂类型的嵌套属性

1 个答案: