我真的需要拿走CTE的结果,并计算数据组的累积值。
数据集是:
PERIOD FT GROUP DEPT VALUE
1 Actual KINDER MATH 200
2 Actual KINDER MATH 363
3 Actual KINDER MATH 366
1 Budget KINDER MATH 457
2 Budget KINDER MATH 60
3 Budget KINDER MATH 158
1 Actual HIGHSCH ENGLISH 456
2 Actual HIGHSCH ENGLISH 745
3 Actual HIGHSCH ENGLISH 125
1 Budget HIGHSCH ENGLISH 364
2 Budget HIGHSCH ENGLISH 158
3 Budget HIGHSCH ENGLISH 200
6 Budget HIGHSCH ENGLISH 502
7 Budget HIGHSCH ENGLISH 650
1 Actual COLL ENGLISH 700
2 Actual COLL ENGLISH 540
3 Actual COLL ENGLISH 160
1 Budget COLL ENGLISH 820
2 Budget COLL ENGLISH 630
3 Budget COLL ENGLISH 800
我想要的是一个额外的列,其中包含每个FT,Group,Dept的累积量。
基本上,我希望它看起来像这样:
PERIOD FT GROUP DEPT VALUE ACC VALUE
1 Actual KINDER MATH 200 200
2 Actual KINDER MATH 363 563
3 Actual KINDER MATH 366 929
1 Budget KINDER MATH 457 457
2 Budget KINDER MATH 60 517
3 Budget KINDER MATH 158 675
1 Actual HIGHSCH ENGLISH 456 456
2 Actual HIGHSCH ENGLISH 745 1201
3 Actual HIGHSCH ENGLISH 125 1326
1 Budget HIGHSCH ENGLISH 364 364
2 Budget HIGHSCH ENGLISH 158 522
3 Budget HIGHSCH ENGLISH 200 722
1 Budget HIGHSCH ENGLISH 502 502
2 Budget HIGHSCH ENGLISH 650 1152
3 Budget HIGHSCH ENGLISH 336 1488
1 Actual COLL ENGLISH 700 700
2 Actual COLL ENGLISH 540 1240
3 Actual COLL ENGLISH 160 1400
1 Budget COLL ENGLISH 820 820
2 Budget COLL ENGLISH 630 1450
3 Budget COLL ENGLISH 800 2250
如果我在SQL 2012中,我会使用类似的东西:
SELECT period
,ft
,group
,dept
,value
,CASE
WHEN FT = 'Actual' THEN SUM(value) OVER (PARTITION BY dept, group, ft ORDER BY period)
ELSE value
END AS AccValue
FROM myTable
但是,我在2008年并且不能使用这种方法,并且难以理解如何为我的数据复制它。
请有人帮忙吗?
答案 0 :(得分:1)
这应该有效。 (我将禁止的列名从“GROUP”更改为“GROUP _”)
with cte (PERIOD, FT, GROUP_, DEPT, VALUE, AccValue) as (select t1.PERIOD, t1.FT, t1.GROUP_, t1.DEPT, t1.VALUE, SUM(t2.VALUE) as AccValue
from myTable t1
join myTable t2 on t1.PERIOD>= t2.PERIOD
and t1.FT = t2.FT
and t1.GROUP_ = t2.GROUP_
and t1.DEPT = t2.DEPT
group by t1.PERIOD, t1.FT, t1.GROUP_, t1.DEPT, t1.VALUE
)
select PERIOD
,FT
,GROUP_
,DEPT
,VALUE
,CASE
WHEN FT = 'Actual' THEN AccValue
ELSE VALUE
END AS AccValue
from cte
order by GROUP_ desc, FT, PERIOD, DEPT desc, VALUE
答案 1 :(得分:1)
简单的INNER JOIN应该可以解决问题。除非我误解了你,你想要的是一个总计,对吗?
此示例使用虚拟数据创建一个虚拟表,然后使用内部联接作为运行总计。从性能角度来看,公用表表达可能更有效。但为了简单起见,内部联接我是优先的。
/* Dummy table */
create table testing1
(col1 int not null identity(1,1),
col2 varchar(5),
col3 int)
insert into testing1
values ('a', 10), ('a', 20), ('a', 30), ('b', 40), ('b', 50)
/* Running total example */
SELECT a.col1
, a.col2
, a.col3
, SUM(b.col3) AS total
FROM testing1 a INNER JOIN testing1 b
ON a.col1 >= b.col1
AND a.col2 = b.col2
GROUP BY a.col1, a.col2, a.col3
ORDER BY a.col1
/* Edit to include Output */
col1 col2 col3 total
1 a 10 10
2 a 20 30
3 a 30 60
4 b 40 40
5 b 50 90